THE ACTUAL QUICKEST FUCKING WAY TO BECOME CHAD (GTFIH NOW)

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kyb

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Let C represent the "Chad" factor, which we'll attempt to compute. We start by taking the square root of confidence (Cf) and adding it to the inverse of awkwardness (Aw) multiplied by charisma (Ch). Then, we raise this sum to the power of fashion sense (Fs) divided by sense of humor (Sh) multiplied by gym hours (Gh) squared. Next, we subtract the product of pick-up lines attempted (Pa) and cologne potency (Cp). Finally, we multiply this result by the ratio of hair gel (Hg) to humility (Hu).
C = sqrt(Cf) + (1 / Aw) * ChC = ((Fs / Sh) * Gh^2) - (Pa * Cp)C = C * (Hg / Hu)C = (Fw / Ns) + (1 / Sl) * ExC = log[(Fw / Ns) + (1 / Sl) * Ex] * Js^2C = (Em / Pu) + (1 / Vg) * (Tc / Ms)
Results on noisy synthetic images SNR 0dB containing two circles of radius 10 with Q640
Now, we take the inverse tangent of eye color (It_ec) divided by the cosine of the facial golden ratio (Cf_gr) multiplied by the sine of the angle of bicep flexion (Sin_bf). This intricate ratio is then added to the tangent of the angle of hip sway (Tan_hs) divided by the arc length of an irresistible wink (Arc_wink)

C = sqrt(Cf) + (1 / Aw) * ChC = ((Fs / Sh) * Gh^2) - (Pa * Cp)C = C * (Hg / Hu)C = (Fw / Ns) + (1 / Sl) * ExC = log[(Fw / Ns) + (1 / Sl) * Ex] * Js^2C = (Em / Pu) + (1 / Vg) * (Tc / Ms)

C = atan(Ec) / cos(Fs) * sin(Bp) + tan(Dm) / arc length(Sm)

This is one of the forums gems and the quickest way i could find to becoming chad, based on these calculations i've made you can ascend to chad within 4 weeks, goodluck!
 
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View attachment 2280860
Let C represent the "Chad" factor, which we'll attempt to compute. We start by taking the square root of confidence (Cf) and adding it to the inverse of awkwardness (Aw) multiplied by charisma (Ch). Then, we raise this sum to the power of fashion sense (Fs) divided by sense of humor (Sh) multiplied by gym hours (Gh) squared. Next, we subtract the product of pick-up lines attempted (Pa) and cologne potency (Cp). Finally, we multiply this result by the ratio of hair gel (Hg) to humility (Hu).
C = sqrt(Cf) + (1 / Aw) * ChC = ((Fs / Sh) * Gh^2) - (Pa * Cp)C = C * (Hg / Hu)C = (Fw / Ns) + (1 / Sl) * ExC = log[(Fw / Ns) + (1 / Sl) * Ex] * Js^2C = (Em / Pu) + (1 / Vg) * (Tc / Ms)
View attachment 2280880Now, we take the inverse tangent of eye color (It_ec) divided by the cosine of the facial golden ratio (Cf_gr) multiplied by the sine of the angle of bicep flexion (Sin_bf). This intricate ratio is then added to the tangent of the angle of hip sway (Tan_hs) divided by the arc length of an irresistible wink (Arc_wink)
C = sqrt(Cf) + (1 / Aw) * ChC = ((Fs / Sh) * Gh^2) - (Pa * Cp)C = C * (Hg / Hu)C = (Fw / Ns) + (1 / Sl) * ExC = log[(Fw / Ns) + (1 / Sl) * Ex] * Js^2C = (Em / Pu) + (1 / Vg) * (Tc / Ms)

C = atan(Ec) / cos(Fs) * sin(Bp) + tan(Dm) / arc length(Sm)


This is one of the forums gems and the quickest way i could find to becoming chad, based on these calculations i've made you can ascend to chad within 4 weeks, goodluck!
dnrd
 
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Entered into my calculator and instantly got my nose bridge retracted and my jaw line became more down, and forward grown. Also expanded my IPD.

Insane modern spellcasting shit

Fruit of evolution type shii
 
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have fun staying an incel.
Entered into my calculator and instantly got my nose bridge retracted and my jaw line became more down, and forward grown. Also expanded my IPD.

Insane modern spellcasting shit

Fruit of evolution type shii
i tried to say it's fucking legit, this forum wont listen..
 
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View attachment 2280860
Let C represent the "Chad" factor, which we'll attempt to compute. We start by taking the square root of confidence (Cf) and adding it to the inverse of awkwardness (Aw) multiplied by charisma (Ch). Then, we raise this sum to the power of fashion sense (Fs) divided by sense of humor (Sh) multiplied by gym hours (Gh) squared. Next, we subtract the product of pick-up lines attempted (Pa) and cologne potency (Cp). Finally, we multiply this result by the ratio of hair gel (Hg) to humility (Hu).
C = sqrt(Cf) + (1 / Aw) * ChC = ((Fs / Sh) * Gh^2) - (Pa * Cp)C = C * (Hg / Hu)C = (Fw / Ns) + (1 / Sl) * ExC = log[(Fw / Ns) + (1 / Sl) * Ex] * Js^2C = (Em / Pu) + (1 / Vg) * (Tc / Ms)
View attachment 2280880Now, we take the inverse tangent of eye color (It_ec) divided by the cosine of the facial golden ratio (Cf_gr) multiplied by the sine of the angle of bicep flexion (Sin_bf). This intricate ratio is then added to the tangent of the angle of hip sway (Tan_hs) divided by the arc length of an irresistible wink (Arc_wink)
C = sqrt(Cf) + (1 / Aw) * ChC = ((Fs / Sh) * Gh^2) - (Pa * Cp)C = C * (Hg / Hu)C = (Fw / Ns) + (1 / Sl) * ExC = log[(Fw / Ns) + (1 / Sl) * Ex] * Js^2C = (Em / Pu) + (1 / Vg) * (Tc / Ms)

C = atan(Ec) / cos(Fs) * sin(Bp) + tan(Dm) / arc length(Sm)


This is one of the forums gems and the quickest way i could find to becoming chad, based on these calculations i've made you can ascend to chad within 4 weeks, goodluck!
BOTB

1687731060469
 
View attachment 2280860
Let C represent the "Chad" factor, which we'll attempt to compute. We start by taking the square root of confidence (Cf) and adding it to the inverse of awkwardness (Aw) multiplied by charisma (Ch). Then, we raise this sum to the power of fashion sense (Fs) divided by sense of humor (Sh) multiplied by gym hours (Gh) squared. Next, we subtract the product of pick-up lines attempted (Pa) and cologne potency (Cp). Finally, we multiply this result by the ratio of hair gel (Hg) to humility (Hu).
C = sqrt(Cf) + (1 / Aw) * ChC = ((Fs / Sh) * Gh^2) - (Pa * Cp)C = C * (Hg / Hu)C = (Fw / Ns) + (1 / Sl) * ExC = log[(Fw / Ns) + (1 / Sl) * Ex] * Js^2C = (Em / Pu) + (1 / Vg) * (Tc / Ms)
View attachment 2280880Now, we take the inverse tangent of eye color (It_ec) divided by the cosine of the facial golden ratio (Cf_gr) multiplied by the sine of the angle of bicep flexion (Sin_bf). This intricate ratio is then added to the tangent of the angle of hip sway (Tan_hs) divided by the arc length of an irresistible wink (Arc_wink)
C = sqrt(Cf) + (1 / Aw) * ChC = ((Fs / Sh) * Gh^2) - (Pa * Cp)C = C * (Hg / Hu)C = (Fw / Ns) + (1 / Sl) * ExC = log[(Fw / Ns) + (1 / Sl) * Ex] * Js^2C = (Em / Pu) + (1 / Vg) * (Tc / Ms)

C = atan(Ec) / cos(Fs) * sin(Bp) + tan(Dm) / arc length(Sm)


This is one of the forums gems and the quickest way i could find to becoming chad, based on these calculations i've made you can ascend to chad within 4 weeks, goodluck!
Still easier than reaching Chad level through looksmaxing.

And here's a simplified version of the equations:

Equation 1: C = sqrt(Cf) + (Ch / Aw)
Equation 2: C = (Fs * Gh^2 / Sh) - (Pa * Cp)
Equation 3: C = C * (Hg / Hu)
Equation 4: C = (Fw / Ns) + (Ex / Sl)
Equation 5: C = log[(Fw / Ns) + (Ex / Sl)] * Js^2
Equation 6: C = (Em / Pu) + (Tc / (Vg * Ms))
Equation 7: C = (atan(Ec) * sin(Bp) / cos(Fs)) + (tan(Dm) / arc length(Sm))
 
the equations simplify to
OP = faggot
 
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Come PMS whore we will schedule a dicksucking session behind a parking....
 
how about this equation:
wake up at 3 am, drop off all of your clothes, stand on your bed and start shouting AMOGUS for 300 times, then a mythical creature called your mother will appear and teleport you to a place called mental hospital where you will mog everyone and your competition will be so low that you could legit psychomaxx and fuck mentally ill women there 24/7 and become the chad sexgod.
 
You will never be any of these niggas Brutal
 

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Great work but your proof is slightly flawed. You forgot to account for hte speed of light
 

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