If you do my chemistry homework I will mark you solution

D

Deleted member 70681

greycelzoomer@proton.me
Joined
Apr 23, 2024
Posts
7,615
Reputation
9,884
EFE3B6AB B02A 4404 8C77 1A4ACAFEA411
 
  • +1
  • JFL
Reactions: org3cel.RR and lost222
Solution
lost222
Problem 5
Mass of water lost: 1.62 g−0.88 g=0.74 g1.62 g−0.88 g=0.74 g.
Moles of CoCl2CoCl2: 0.88 g129.83 g/mol≈0.00678 mol129.83 g/mol0.88 g≈0.00678 mol.
Moles of H2OH2O: 0.74 g18.015 g/mol≈0.0411 mol18.015 g/mol0.74 g≈0.0411 mol.
Mole ratio: 0.04110.00678≈60.006780.0411≈6.
Formula of hydrate: CoCl2⋅6 H2OCoCl2⋅6 H2O
Name of hydrate: Cobalt(II) chloride hexahydrate

Problem 6
Mass of water lost: 1.04 g−0.61 g=0.43 g1.04 g−0.61 g=0.43 g.
Moles of NiSO4NiSO4: 0.61 g154.76 g/mol≈0.00394 mol154.76 g/mol0.61 g≈0.00394 mol.
Moles of H2OH2O: 0.43 g18.015 g/mol≈0.0239 mol18.015 g/mol0.43 g≈0.0239 mol.
Mole ratio: 0.02390.00394≈60.003940.0239≈6.
Formula of hydrate: NiSO4⋅6 H2ONiSO4⋅6 H2O...
whats with you. cant do it yourself?
 
  • +1
Reactions: Balkanmogger1446 and Deleted member 70681
Problem 5
Mass of water lost: 1.62 g−0.88 g=0.74 g1.62 g−0.88 g=0.74 g.
Moles of CoCl2CoCl2: 0.88 g129.83 g/mol≈0.00678 mol129.83 g/mol0.88 g≈0.00678 mol.
Moles of H2OH2O: 0.74 g18.015 g/mol≈0.0411 mol18.015 g/mol0.74 g≈0.0411 mol.
Mole ratio: 0.04110.00678≈60.006780.0411≈6.
Formula of hydrate: CoCl2⋅6 H2OCoCl2⋅6 H2O
Name of hydrate: Cobalt(II) chloride hexahydrate

Problem 6
Mass of water lost: 1.04 g−0.61 g=0.43 g1.04 g−0.61 g=0.43 g.
Moles of NiSO4NiSO4: 0.61 g154.76 g/mol≈0.00394 mol154.76 g/mol0.61 g≈0.00394 mol.
Moles of H2OH2O: 0.43 g18.015 g/mol≈0.0239 mol18.015 g/mol0.43 g≈0.0239 mol.
Mole ratio: 0.02390.00394≈60.003940.0239≈6.
Formula of hydrate: NiSO4⋅6 H2ONiSO4⋅6 H2O
Name of hydrate: Nickel(II) sulfate hexahydrate

Problem 7
Molar mass of K2S⋅5 H2OK2S⋅5 H2O:
K2SK2S: 2(39.10)+32.07=110.27 g/mol2(39.10)+32.07=110.27 g/mol
H2OH2O: 5(18.015)=90.075 g/mol5(18.015)=90.075 g/mol
Total molar mass: 110.27+90.075=200.345 g/mol110.27+90.075=200.345 g/mol
Percent water: 90.075200.345×100≈44.96%200.34590.075×100≈44.96%
Name of hydrate: Potassium sulfide pentahydrate
Percent of water: 44.96%44.96%
 
  • Love it
  • JFL
  • +1
Reactions: lovebeingamanlet, bpcq, Deathninja328 and 3 others
Solution
Problem 5
Mass of water lost: 1.62 g−0.88 g=0.74 g1.62 g−0.88 g=0.74 g.
Moles of CoCl2CoCl2: 0.88 g129.83 g/mol≈0.00678 mol129.83 g/mol0.88 g≈0.00678 mol.
Moles of H2OH2O: 0.74 g18.015 g/mol≈0.0411 mol18.015 g/mol0.74 g≈0.0411 mol.
Mole ratio: 0.04110.00678≈60.006780.0411≈6.
Formula of hydrate: CoCl2⋅6 H2OCoCl2⋅6 H2O
Name of hydrate: Cobalt(II) chloride hexahydrate

Problem 6
Mass of water lost: 1.04 g−0.61 g=0.43 g1.04 g−0.61 g=0.43 g.
Moles of NiSO4NiSO4: 0.61 g154.76 g/mol≈0.00394 mol154.76 g/mol0.61 g≈0.00394 mol.
Moles of H2OH2O: 0.43 g18.015 g/mol≈0.0239 mol18.015 g/mol0.43 g≈0.0239 mol.
Mole ratio: 0.02390.00394≈60.003940.0239≈6.
Formula of hydrate: NiSO4⋅6 H2ONiSO4⋅6 H2O
Name of hydrate: Nickel(II) sulfate hexahydrate

Problem 7
Molar mass of K2S⋅5 H2OK2S⋅5 H2O:
K2SK2S: 2(39.10)+32.07=110.27 g/mol2(39.10)+32.07=110.27 g/mol
H2OH2O: 5(18.015)=90.075 g/mol5(18.015)=90.075 g/mol
Total molar mass: 110.27+90.075=200.345 g/mol110.27+90.075=200.345 g/mol
Percent water: 90.075200.345×100≈44.96%200.34590.075×100≈44.96%
Name of hydrate: Potassium sulfide pentahydrate
Percent of water: 44.96%44.96%
Holy gpt
 
  • JFL
Reactions: lost222

Final Answers:​

5.
Formula of hydrate = CoCl₂·6H₂O
Name of hydrate = Cobalt(II) chloride hexahydrate
6.

Formula of hydrate = NiSO₄·6H₂O
Name of hydrate = Nickel(II) sulfate hexahydrate
7.

% of water = 44.96%
Name of hydrate = Potassium sulfide pentahydrate
Can you show work Mr shilinski will get mad if I dont he will acccuse me if cheating
 
  • JFL
Reactions: lost222

Similar threads

D
Replies
13
Views
179
LLcel
LLcel
D
Replies
5
Views
78
Doryphoros
Doryphoros
D
Replies
9
Views
143
Deleted member 70681
D
D
Replies
2
Views
69
Deleted member 70681
D

Users who are viewing this thread

Back
Top