7, 343, 1728, 373248, ?

a) I don't believe you, you were writing retarded shit

b) if you don't explain your method you don't get credit
look at my first reply itt. I had already figured this out
 
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wasn't the solution I had but it fits so who is to say what is and isn't a right answer
It doesnt fit. Theres no role of 7 in the series. If you think that it fits then i dont need to know your solution cause its probably equally shit
 
wasn't the solution I had but it fits so who is to say what is and isn't a right answer
it doesn’t fit. The first 7 doesn’t fit in that solution.
 
I am going to fail my test tomorrow because of his series
 
OP is wasting our time:feelswhy:
I thought it was a series out of those IQ Tests. But since he made it im doubting it as well ngl. Op has a history of trying to come across as super smart
 
I thought it was a series out of those IQ Tests. But since he made it in doubting it as well ngl
the sequences in those iq tests were also made by some guy btw
 
first number can be a base
Yeah but then the base would have to be essential. Like the Fibonacci series. But in his solution the 7 is absolutly pointless

Without the 7 the series would be the same. Making the 7 useless
 
Yeah but then the base would have to be essential. Like the Fibonacci series. But in his solution the 7 is absolutly pointless

Without the 7 the series would be the same. Making the 7 useless
wtf are you even saying you just have a_0=x and then define it recursively
 
the sequences in those iq tests were also made by some guy btw
Not just one. There are plenty of ppl looking over them. You as a single person can make mistakes and be oblivious to them
 
wtf are you even saying you just have a_0=x and then define it recursively
Look

In this Solution here
7^3 = 343
12^3 = 1728
72^3 = 373248
and 7 x 12 -72 = 12
12 x 12 - 72 = 72
so 72 x 12 - 72 = 792
and 792^3 = 496793088

There is no explanation for the first 7 and neither is it a base to compute the 343

You might argue the 7 is the base in the 7^3 but then the next step would be 343^3 following that logic. Which isn’t the case
 
@Harold O'brien dm me the solution and I see if it makes sense or not. So others can either stop or keep trying
 
Look

In this Solution here


There is no explanation for the first 7 and neither is it a base to compute the 343

You might argue the 7 is the base in the 7^3 but then the next step would be 343^3 following that logic. Which isn’t the case
a_0=7

a_n= [12(a_{n-1})-72]^3
 
i see absolutely zero relation between the first and last 2 numbers tbh
except the power of 3, the relation must be something very vague
i can write random numbers which would in theory be a vague solution but i dont think its worth it
i give up
 
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you could have

b_0=7

b_n= 12(a_{n-1})-72

a_n=(b_n)^3
 
i see absolutely zero relation between the first and last 2 numbers tbh
except the power of 3, the relation must be something very vague
i can write random numbers which would in theory be a vague solution but i dont think its worth it
i give up
Starting to think his series isn’t really a series ngl
 
what also bugs me is how 343 is related to 1728, because 1728 is (3*4)^3
but i dont think this is the right path
 
i see absolutely zero relation between the first and last 2 numbers tbh
except the power of 3, the relation must be something very vague
i can write random numbers which would in theory be a vague solution but i dont think its worth it
i give up
formal:

represent numbers as cxd where c is the first digit, d is the last digit and x is all digits inbetween

let f,g and h be functions such that f(cxd) =c, g(cxd)=x, h(cxd)=d

then intended solution was a_0=7, a_{n+1}= g(a_n)^3 * f(a_n)^g(a_n)

that was probably way too formal


informal:

first digit of last term to the power of last digit of last term multiplied by middle of last term cubed

ie (3^3)*(4^3)=1728 or (72^3)*(1^8)=373248

so ? would be (7324^3)*(3^8)
 
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formal:

represent numbers as cxd where c is the first digit, d is the last digit and x is all digits inbetween

let f,g and h be functions such that f(cxd) =c, g(cxd)=x, h(cxd)=d

then intended solution was a_0=7, a_{n+1}= g(a_n)^3 * f(a_n)^g(a_n)

that was probably way too formal


informal:

first digit of last term to the power of last digit of last term multiplied by middle of last term cubed

ie (3^3)*(4^3)=1728 or (72^3)*(1^8)=373248

so ? would be (7324^3)*(3^8)
That doesn’t work.



You can’t compute

a_1 out of a_0
 
if c=x=d then f(.)=h(.)=1
Lol

What’s next. A series where ever number has its own exception? You can’t fck up a series like that and then pretend it was all calculated. Besides that this series is dumb af


The 5th number is to the power of 15 lol you don’t even know the real 5th number yourself.
 
Lol

What’s next. A series where ever number has its own exception? You can’t fck up a series like that and then pretend it was all calculated. Besides that this series is dumb af


The 5th number is to the power of 15 lol you don’t even know the real 5th number yourself.
the rule is very intuitive, just difficult to formalize

people who couldn't solve getting mad, nothing new
 
the rule is very intuitive, just difficult to formalize

people who couldn't solve getting mad, nothing new
Man you made a mistake and are too narci to realize or accept it.

This series is 1) not solveable with logic as you needed to introduce an exception.


2) you don’t even know the exact 5th number cuz your calculator doesn’t give you exact numbers to the power of 15

3) even if you started with 343 and didn’t have that 7 in it that rule is the most random rule I’ve ever seen, which also would make the 5th number do outrageously large


But yeah as it stands that series is false due to the 7
 
Man you made a mistake and are too narci to realize or accept it.

This series is 1) not solveable with logic as you needed to introduce an exception.


2) you don’t even know the exact 5th number cuz your calculator doesn’t give you exact numbers to the power of 15

3) even if you started with 343 and didn’t have that 7 in it that rule is the most random rule I’ve ever seen


But yeah as it stands that series is false due to the 7
stfu midwit
 
stfu midwit
You better learn that we all make mistakes and you aren’t as smart as you think. I had to learn it the hard way by having a doctor In IT basically tell me I did some retarded shit.
 
You better learn that we all make mistakes and you aren’t as smart as you think. I had to learn it the hard way by having a doctor In IT basically tell me I did some retarded shit.
one of your "criticisms" is literally number too big I don't like it lmfao
 
one of your "criticisms" is literally number too big I don't like it lmfao
One of the criticism. Exactly. The most important one was that your series as you wrote it down doesn’t work (without exceptions).


What you did is the equivalent of focusing on a typo…


Your series doesn’t work and you didn’t think That one through
 
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One of the criticism. Exactly. The most important one was that your series as you wrote it down doesn’t work without exceptions.


That’s the equivalent of focusing on a typo…


Your series doesn’t work and you didn’t think That one through
it's intuitively very clear that if you have only one digit you treat it as the middle one

you are just mad because you didn't get it, and that's ok
 
it's intuitively very clear that if you have only one digit you treat it as the middle one

you are just mad because you didn't get it, and that's ok
I don’t judge people for Doing a mistake. Everyone does that. But people who do them and have an attitude like you, can’t accept their mistakes.

It’s not even anything at stake here. Relax
 
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I don’t judge people for Doing a mistake. Everyone does that. But people who do them and have an attitude like you, can’t accept their mistakes and thus also can’t learn. Those people are an issue.


It’s not even anything at stake here. Relax
it's not a mistake, retard

caging at the condescending attitude to project your own frustrations though. this is where I am in my element
 
it's not a mistake, retard

caging at the condescending attitude to project your own frustrations though. this is where I am in my element
Gladly I’m not like you anymore. Thinking I’m super smart n always right.
 
the 72 in 1728 is a dead giveaway
cant believe i didnt notice it, after that the problem is a piece of cake
 
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the 72 in 1728 is a dead giveaway
cant believe i didnt notice it, after that the problem is a piece of cake
You think it makes sense?
 
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You think it makes sense?
it does
why wouldnt it
turns out its not as vague as i thought, and like i said, the 72 makes it obvious, yet i somehow didnt notice it
 
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it does
why wouldnt it
turns out its not as vague as i thought, and like i said, the 72 makes it obvious, yet i somehow didnt notice it
i don’t see how the 72 makes it obvious at all


Also still the issue with the 7 that doesn’t fit the series as you can’t Compute a1 out of a0
 
it does
why wouldnt it
turns out its not as vague as i thought, and like i said, the 72 makes it obvious, yet i somehow didnt notice it
i don’t see how the 72 makes it obvious at all


Also still the issue with the 7 that doesn’t fit the series as you can’t Compute a1 out of a0
Even if we took out the 7 and only had the 343 1728 and last number, so it would be a valid series, i still don’t see how the 72 makes anything obvious here as you still would have to 72^3*8
 
Even if we took out the 7 and had the 343 1728 and last number, so it would be a valid series, i still don’t see how the 72 makes anything obvious here as you still would have to 72^3*8
its 72^3 x 1^8 in other words 72^3 x 1
 
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