7, 343, 1728, 373248, ?

[Deleted member 18258]

Ah yeah you are right. Wouldn’t have seen it either way tho

Fair enough I've never seen a sequence with rules like these either

 

[Deleted member 13787]

Even if we took out the 7 and had the 343 1728 and last number only i still don’t see how the 72 makes anything obvious here as you still would have to 72^3*8

where did you get *8
373248 is 72^3, and its obvious
then you see the 72 in 1728
from then on you should logically think "hmm, we might need to take the 72 from the middle of the previous number and cube it"
you go back to 1728, and try to cube the middle of 343, so you get 64
you think, "ok, so in order to get 1728 and have it involve i need to cube the 4 and multiply it by 27"
"oh wait, 3^3 is 27, which happens to be the first an last digit of the prev number, could it be, that this is the rule?"
you take 72^3 from the middle of 1728 and you multiply it by 1^8, and yeah, obviously it works
thats how you figure it out easily, you just need to notice the 72 in 1728

 

[Deleted member 12217]

where did you get *8
373248 is 72^3, and its obvious
then you see the 72 in 1728
from then on you should logically think "hmm, we might need to take the 72 from the middle of the previous number and cube it"
you go back to 1728, and try to cube the middle of 343, so you get 64
you think, "ok, so in order to get 1728 and have it involve i need to cube the 4 and multiply it by 27"
"oh wait, 3^3 is 27, which happens to be the first an last digit of the prev number, could it be, that this is the rule?"
you take 72^3 from the middle of 1728 and you multiply it by 1^8, and yeah, obviously it works
thats how you figure it out easily, you just need to notice the 72 in 1728

Yea the 8 was just wrong .


Yeah. I wonder if someone would see it like this.

 

[youngmax]

@youngmax

first one is 7 2nd one is 7 cubed.

 

[looksmaxxed]

all math based riddles can be easily solved by running a script where all arithmetic functions are tested to check for consistent patterns.

doing well on math based test=insect iq

 

[Harold O'brien]

all math based riddles can be easily solved by running a script where all arithmetic functions are tested to check for consistent patterns.

doing well on math based test=insect iq

No they can't, insect iq detected

Maybe a regression for polynomials but only works for extremely simple cases. Most sequences can't be solved by an algorithm, but you have to be careful and check they aren't on oeis first