boyos get smarter and solve it for me

[cryptt]

peasant
what would happen to resistance if diameter is doubled
electricity question
@imontheloose

 

[cryptt]

b

 

[cryptt]

nigga ew fuck u

 

[Clark]

nigga ew fuck u

This could be us

 

[cryptt]

This could be us

niggno what is this gay infiltration on org u cannot take my 10x8

 

[truecelitover]

The area quadruples but as the length of the wire increases the resistance starts to increase again

 

[truecelitover]

Basically youll be able to have a higher load the larger the surface area

 

[got.daim]

peasant
what would happen to resistance if diameter is doubled
electricity question
@imontheloose

I have more rep than you, you're the serf

 

[cryptt]

I have more rep than you, you're the serf

proud of u bhai u have more reps than me on a incel forum

The area quadruples but as the length of the wire increases the resistance starts to increase again

so like rho x l/4pie 16dsquare? and then we take 4 common and send it below r

 

[got.daim]

proud of u bhai u have more reps than me on a incel forum

so like rho x l/4pie 16dsquare? and then we take 4 common and send it below r

use chatgpt

 

[cryptt]

View attachment 3446830
use chatgpt

caged
did use chatgpt but the explaination was mostly theoretical

 

[truecelitover]

proud of u bhai u have more reps than me on a incel forum

so like rho x l/4pie 16dsquare? and then we take 4 common and send it below r

yeah youll be left with
R
—
4

 

[truecelitover]

Its about wire resistance and length / cross section area

 

[normaler_rasista]

peasant
what would happen to resistance if diameter is doubled
electricity question
@imontheloose

If the diameter of a conductor is doubled, the resistance of the conductor will decrease. Specifically, the resistance will be reduced by a factor of 4.

This is because resistance \( R \) is inversely proportional to the cross-sectional area \( A \) of the conductor, and the area \( A \) is proportional to the square of the diameter (\( A \propto d^2 \)).

So, if the diameter is doubled, the area increases by a factor of four, and since resistance decreases with an increase in area, the resistance will decrease by a factor of 4.

 

[truecelitover]

caged
did use chatgpt but the explaination was mostly theoretical

It is theoretical. Theres other factors that will play into impedance like temperature and material used.

 

[truecelitover]

If the diameter of a conductor is doubled, the resistance of the conductor will decrease. Specifically, the resistance will be reduced by a factor of 4.

This is because resistance \( R \) is inversely proportional to the cross-sectional area \( A \) of the conductor, and the area \( A \) is proportional to the square of the diameter (\( A \propto d^2 \)).

So, if the diameter is doubled, the area increases by a factor of four, and since resistance decreases with an increase in area, the resistance will decrease by a factor of 4.

Nigga we dont want your google copy and paste

 

[normaler_rasista]

Nigga we dont want your google copy and paste

I don't do normie shit

 

[cryptt]

yeah youll be left with
R
—
4

same thing happens when r is doubled?

 

[truecelitover]

same thing happens when r is doubled?

R is just resistance. If resistance raises then you have less current and more heat. you would have to increase voltage to maintain the same current.

 

[cryptt]

R is just resistance. If resistance raises then you have less current and more heat. you would have to increase voltage to maintain the same current.

no not the resistance if radius is doubled the resistance would be r/4 too right

 

[cryptt]

R is just resistance. If resistance raises then you have less current and more heat. you would have to increase voltage to maintain the same current.

why more heat? the charges colliding or smth?

 

[truecelitover]

why more heat? the charges colliding or smth?

Yes

no not the resistance if radius is doubled the resistance would be r/4 too right

Well the radius doubled would just be the original diameter if im reading your question right but i might not be. The radius would need quadrupled to be the same area.

 

[truecelitover]

Stranded wire mathematically is not as simple as solid wire but for theoretical purposes its relatively the same for this answer.

 

[imontheloose]

peasant
what would happen to resistance if diameter is doubled
electricity question
@imontheloose

R=resistivity*L/A

So R is inversely prop to A, assuming it’s a circular cross-section, A=(pi*d^2)/4. If d doubles you have A1=(pi*(2d)^2)/4 so A1=pi*d^2 which means A1=4A (the cross sectional area quadruples when d is doubled) so thus R1=R/4 so the resistance quarters when d doubles

 

[cryptt]

R=resistivity*L/A

So R is inversely prop to A, assuming it’s a circular cross-section, A=(pi*d^2)/4. If d doubles you have A1=(pi*(2d)^2)/4 so A1=pi*d^2 which means A1=4A (the cross sectional area quadruples when d is doubled) so thus R1=R/4 so the resistance quarters when d doubles

pi*dsquare4 but why divide it by 4

 

[imontheloose]

pi*dsquare4 but why divide it by 4

the area of a circle is pi*r^2 right? you know r=d/2 so substitute that in and youll have pi*(d/2)^2 and thus pi*(d^2)/4

 

[cryptt]

the area of a circle is pi*r^2 right? you know r=d/2 so substitute that in and youll have pi*(d/2)^2 and thus pi*(d^2)/4

oh