Kelsey Merritt in candid

How many standard deviations above the mean (5/10) is she (full body for prime-age females)?


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how did you come up with how much percenatile each rating is?
some skewed deviation model?
Probability=NORMDIST(X, 5, 1, FALSE)
Percentile=NORMDIST(X, 5, 1, TRUE) * 100

Which is literally not skewed.
 
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Isn’t that phenotype?
Face shape, nose shape, eye shape, lips, cheekbones, jawline, body type, limb length, body hair, hair texture, etc. are all part of phenotype.
 
Probability=NORMDIST(X, 5, 1, FALSE)
Percentile=NORMDIST(X, 5, 1, TRUE) * 100

Which is literally not skewed.
Thanks. I checked it, and you are right. You used standard/normal distribution.
The rarerity of an 8/10 and shit, always surprises me initially, when seeing da numbers and it being like.

for example.
in a small city of 150.000 people. 75000 dudes and 75000 females.
there will only be 100 females and 100 dudes, that are an 8/10. Insane low numbers, and it makes it statisticaklly very unlikely even for women in da average ranges to ever ever, have a shot to be with an 8/10 dude. Aka, 75.000 women competing for the 100 dudes that are 8/10
 

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