prove that "X x X - 1 = ℂ" is false

[Deleted member 33275]

 

[Deleted member 25534]

corny nigger

 

[Ruakh]

go to r/maths faggot

 

[Deleted member 33275]

go to r/maths faggot

i did, they couldn't do it

 

[Debetro]

i have an easier time explaining why niggers are so stupid than solving this shit

 

[Ruakh]

i did, they couldn't do it

so you came to an incel forum to ask someone to solve this shit

 

[Deleted member 33275]

so you came to an incel forum to ask someone to solve this shit

a lot of 130+ guys here

 

[Ruakh]

no one is gonna be willing so solve this go to https://www.freemathhelp.com/forum/ maybe

 

[Deleted member 33275]

no one is gonna be willing so solve this go to https://www.freemathhelp.com/forum/ maybe

doesn't hurt to try

 

[rl⠀]

To prove that the equation "X x X - 1 = ℂ" is false, we need to demonstrate that there is no value of X that satisfies this equation. Let's break down the equation and analyze it step by step.

The equation "X x X - 1 = ℂ" can be rewritten as "X^2 - 1 = ℂ," where X^2 represents X multiplied by itself. The symbol ℂ represents the set of complex numbers.

To solve this equation, we need to find the value of X that makes the equation true. However, it is important to note that the left side of the equation is a real number (X^2 - 1), while the right side (ℂ) represents a set of complex numbers. Therefore, it is impossible for these two sides to be equal.

In mathematics, a complex number is defined as a number of the form a + bi, where "a" and "b" are real numbers and "i" represents the imaginary unit (√-1). Complex numbers cannot be directly compared to real numbers because they have both real and imaginary components.

Since the left side of the equation represents a real number and the right side represents a set of complex numbers, it is evident that there is no value of X that can satisfy this equation. Therefore, we can conclude that "X x X - 1 = ℂ" is false.

In summary, the equation "X x X - 1 = ℂ" is false because it equates a real number (X^2 - 1) to a set of complex numbers (ℂ), which cannot be equal.

 

[Deleted member 33275]

To prove that the equation "X x X - 1 = ℂ" is false, we need to demonstrate that there is no value of X that satisfies this equation. Let's break down the equation and analyze it step by step.

The equation "X x X - 1 = ℂ" can be rewritten as "X^2 - 1 = ℂ," where X^2 represents X multiplied by itself. The symbol ℂ represents the set of complex numbers.

To solve this equation, we need to find the value of X that makes the equation true. However, it is important to note that the left side of the equation is a real number (X^2 - 1), while the right side (ℂ) represents a set of complex numbers. Therefore, it is impossible for these two sides to be equal.

In mathematics, a complex number is defined as a number of the form a + bi, where "a" and "b" are real numbers and "i" represents the imaginary unit (√-1). Complex numbers cannot be directly compared to real numbers because they have both real and imaginary components.

Since the left side of the equation represents a real number and the right side represents a set of complex numbers, it is evident that there is no value of X that can satisfy this equation. Therefore, we can conclude that "X x X - 1 = ℂ" is false.

In summary, the equation "X x X - 1 = ℂ" is false because it equates a real number (X^2 - 1) to a set of complex numbers (ℂ), which cannot be equal.

I'm kinda on the same page here. IMO, the statement "X x X - 1 = ℂ" is false because it equates the result of a mathematical operation, specifically multiplication, to a set of numbers, the complex numbers. However, the two sides of the equation are not comparable.
Let's break down the statement:

1. X x X - 1: This represents the result of multiplying the variable X by itself (X x X) and then subtracting 1 from that product. In mathematical notation, this can be represented as X^2 - 1.
2. ℂ: This symbol represents the set of complex numbers.

The problem here is that X^2 - 1 is an algebraic expression that depends on the value of X, whereas ℂ represents an entire set of numbers with both real and imaginary components.

The set of complex numbers (ℂ) includes all numbers of the form a + bi, where "a" and "b" are real numbers and "i" is the imaginary unit (√-1). Complex numbers cannot be directly equated to algebraic expressions that depend on a single variable, like X^2 - 1.
To illustrate this further, let's consider some examples:

1. If X = 2:X x X - 1 = 2 x 2 - 1 = 3ℂ = {a + bi} where a, b ∈ ℝ

The value of X^2 - 1 is 3, which is a real number. However, ℂ represents a set of complex numbers, not just a single value.

1. If X = 3:X x X - 1 = 3 x 3 - 1 = 8ℂ = {a + bi} where a, b ∈ ℝ

The value of X^2 - 1 is 8, which, again, is a real number. However, it still doesn't correspond to the entire set of complex numbers.
Therefore, we can see that the statement "X x X - 1 = ℂ" is invalid and cannot be considered true because it compares an algebraic expression involving X to the set of complex numbers, which is a completely different mathematical entity.

 

[JackTheKnife]

Do you still think about your mortality? coping with vikings?

 

[Deleted member 33275]

Do you still think about your mortality? coping with vikings?

just downloaded witcher

 

[Deleted member 25534]

I'm kinda on the same page here. IMO, the statement "X x X - 1 = ℂ" is false because it equates the result of a mathematical operation, specifically multiplication, to a set of numbers, the complex numbers. However, the two sides of the equation are not comparable.
Let's break down the statement:

1. X x X - 1: This represents the result of multiplying the variable X by itself (X x X) and then subtracting 1 from that product. In mathematical notation, this can be represented as X^2 - 1.
2. ℂ: This symbol represents the set of complex numbers.

The problem here is that X^2 - 1 is an algebraic expression that depends on the value of X, whereas ℂ represents an entire set of numbers with both real and imaginary components.

The set of complex numbers (ℂ) includes all numbers of the form a + bi, where "a" and "b" are real numbers and "i" is the imaginary unit (√-1). Complex numbers cannot be directly equated to algebraic expressions that depend on a single variable, like X^2 - 1.
To illustrate this further, let's consider some examples:

1. If X = 2:X x X - 1 = 2 x 2 - 1 = 3ℂ = {a + bi} where a, b ∈ ℝ

The value of X^2 - 1 is 3, which is a real number. However, ℂ represents a set of complex numbers, not just a single value.

1. If X = 3:X x X - 1 = 3 x 3 - 1 = 8ℂ = {a + bi} where a, b ∈ ℝ

The value of X^2 - 1 is 8, which, again, is a real number. However, it still doesn't correspond to the entire set of complex numbers.
Therefore, we can see that the statement "X x X - 1 = ℂ" is invalid and cannot be considered true because it compares an algebraic expression involving X to the set of complex numbers, which is a completely different mathematical entity.

this schizo is talking tk himself

 

[JackTheKnife]

just downloaded witcher

Are you still on the edge and cope with tv shows like the vikings to cope with your mortality? or you watch / play the witcher cuz

 

[Deleted member 33275]

Are you still on the edge and cope with tv shows like the vikings to cope with your mortality? or you watch / play the witcher cuz

nah, joking aside, i've had my tv on for maybe 3 hours in the last 2 months.

made a huge leap with my law firm so i became obsessed with that and a couple of girls i'm seeing

i dont play video games. played fifa/nba with friends before and that's it.

 

[rl⠀]

this schizo is talking tk himself

only way to have a good conversation in this shithole

@_MVP_ could be another good guy to talk to, but his nurses probably sedated him for the day

 

[Deleted member 33275]

this schizo is talking tk himself

1. schizoid, not schizo. retard.
2. rl is a different person, the mods can easily check the IPs.
3. I have you blocked. Dravidian tier looksmax user.

 

[Deleted member 21863]

The given statement, "X x X - 1 = ℂ" seems to be a misinterpretation or confusion of mathematical terms. Let's break it down:

- "X x X - 1" appears to be an algebraic expression, where "X" is a variable, and the operation is to square X (X times X) and subtract 1.

- "ℂ" typically denotes the set of all complex numbers, which is an infinite set of numbers in the form a + bi, where a and b are real numbers and i is the square root of -1.

An algebraic expression like "X x X - 1" represents a single number (whether real or complex), depending on the value of X, while ℂ represents a set of infinite numbers. Therefore, it's logically false to equate an expression representing a single number to a set representing infinite numbers.

The statement could be made correct by saying "X x X - 1 ∈ ℂ" which means the result of the expression "X x X - 1" belongs to the set of all complex numbers, since the set of complex numbers contains all real numbers and all values of "X x X - 1" are real.

 

[Deleted member 33275]

The given statement, "X x X - 1 = ℂ" seems to be a misinterpretation or confusion of mathematical terms. Let's break it down:

- "X x X - 1" appears to be an algebraic expression, where "X" is a variable, and the operation is to square X (X times X) and subtract 1.

- "ℂ" typically denotes the set of all complex numbers, which is an infinite set of numbers in the form a + bi, where a and b are real numbers and i is the square root of -1.

An algebraic expression like "X x X - 1" represents a single number (whether real or complex), depending on the value of X, while ℂ represents a set of infinite numbers. Therefore, it's logically false to equate an expression representing a single number to a set representing infinite numbers.

The statement could be made correct by saying "X x X - 1 ∈ ℂ" which means the result of the expression "X x X - 1" belongs to the set of all complex numbers, since the set of complex numbers contains all real numbers and all values of "X x X - 1" are real.

this got me thinking, ngl

 

[_MVP_]

@Duncan_