Proving 0.999....♾ = 1

Seven

Seven

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Proving 0.999....♾ = 1
not around or round figure
but equal to


so ,

let x = 0.999....♾ - eq 1

(then multiply both sides by 10)

so 10x = 9.999....♾ - eq 2

(now subtract eq 1 from eq 2 )


10x = 9.999....♾

- 1x = 0.999....♾
__________________


9x = 9....♾

so x = 9....♾/9

which is equal to 1....♾


, hence proved

● also this eq will only work if there is ♾(infinite) to it , if not it won't work example -

let x = 0.999 - eq 1

multiply both sides by 10

10x = 9.99 - eq 2

now subtract eq 1 from eq 2

so 10x = 9.99

- 1x = 0.999
______________

9x = 8.991


● so it only works when there is infinite to it

HENCE PROVED





 
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@Jattgymmaxx @messi1 @literallytaxidriver
 
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Proving 0.999....♾ = 1
not around or round figure
but equal to


so ,

let x = 0.999....♾ - eq 1

(then multiply both sides by 10)

so 10x = 9.999....♾ - eq 2

(now subtract eq 1 from eq 2 )


10x = 9.999....♾

- 1x = 0.999....♾
__________________


9x = 9....♾

so x = 9....♾/9

which is equal to 1....♾


, hence proved

● also this eq will only work if there is ♾(infinite) to it , if not it won't work example -

let x = 0.999 - eq 1

multiply both sides by 10

10x = 9.99 - eq 2

now subtract eq 1 from eq 2

so 10x = 9.99

- 1x = 0.999
______________

9x = 8.991


● so it only works when there is infinite to it

HENCE PROVED





nah
 
Proving 0.999....♾ = 1
not around or round figure
but equal to


so ,

let x = 0.999....♾ - eq 1

(then multiply both sides by 10)

so 10x = 9.999....♾ - eq 2

(now subtract eq 1 from eq 2 )


10x = 9.999....♾

- 1x = 0.999....♾
__________________


9x = 9....♾

so x = 9....♾/9

which is equal to 1....♾


, hence proved

● also this eq will only work if there is ♾(infinite) to it , if not it won't work example -

let x = 0.999 - eq 1

multiply both sides by 10

10x = 9.99 - eq 2

now subtract eq 1 from eq 2

so 10x = 9.99

- 1x = 0.999
______________

9x = 8.991


● so it only works when there is infinite to it

HENCE PROVED





Anything for positive rep ratio
 
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ratio is crazy
 
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Proving 0.999....♾ = 1
not around or round figure
but equal to


so ,

let x = 0.999....♾ - eq 1

(then multiply both sides by 10)

so 10x = 9.999....♾ - eq 2

(now subtract eq 1 from eq 2 )


10x = 9.999....♾

- 1x = 0.999....♾
__________________


9x = 9....♾

so x = 9....♾/9

which is equal to 1....♾


, hence proved

● also this eq will only work if there is ♾(infinite) to it , if not it won't work example -

let x = 0.999 - eq 1

multiply both sides by 10

10x = 9.99 - eq 2

now subtract eq 1 from eq 2

so 10x = 9.99

- 1x = 0.999
______________

9x = 8.991


● so it only works when there is infinite to it

HENCE PROVED





Don't care math is jester
 
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couldve just wrote 0.9 with a dot above the 9 mate
 
Nostalgic
 
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i learnt this in 7th grade btw
 
Proving 0.999....♾ = 1
not around or round figure
but equal to


so ,

let x = 0.999....♾ - eq 1

(then multiply both sides by 10)

so 10x = 9.999....♾ - eq 2

(now subtract eq 1 from eq 2 )


10x = 9.999....♾

- 1x = 0.999....♾
__________________


9x = 9....♾

so x = 9....♾/9

which is equal to 1....♾


, hence proved

● also this eq will only work if there is ♾(infinite) to it , if not it won't work example -

let x = 0.999 - eq 1

multiply both sides by 10

10x = 9.99 - eq 2

now subtract eq 1 from eq 2

so 10x = 9.99

- 1x = 0.999
______________

9x = 8.991


● so it only works when there is infinite to it

HENCE PROVED





7e7.png
 

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