GuyFromSingapore
I mog Cavill, O'Pry and Barrett
- Joined
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[17 × 7 + (12 × 3)] × 2 = 305
20 ÷ 3 = 7(round off)
7 × 9(teddy bears) = 63
305 + 63 = 368
305 - 63 = 224
17 × 12 = 204
17 × 4 = 68
224 - 68 = 156
156 ÷ 12 = 13
17 × 3 = 51
12 × 12 = 144
305 - 195 = 110
110 ÷ 9 = 12(round off)
305 ÷ 12 = 25
25 = 5 × 5
18 = 2 × 3 × 3
305 ÷ 17 = 18
25 + 9 = 34
30 + 8 = 38(not divisible by 3)
20 + 10 = 30(divisible by 3)
10 × 9 = 90
305 - 90 = 215
20 × 12 + 10 × 17 = 240 + 170 = 410
Pair A: 12 + 12 + 17 + 9 = 50
Pair B: 17 + 17 + 12 + 9 = 55
So... 50 × 5 = 250
250 + 55 = 305
THEREFORE THE ANSWER IS THERE WERE 5 PAIR As and 1 PAIR Bs.
There was only 1 girl in pair A which × 5 means 5 girls in pair As and + 1 pair B where theres 2 girls = 7
3 × 5 + 3 = 18 students in total
6 × 9 = 54
305 - 54 = 251
7 × 17 = 119
251 - 119 = 132
132 ÷ 12 = 11
11 boys and 7 girls
ANSWER: 11 boys × 12 books each + 7 girls × 17 books each + 6 × 9 teddies = 132 + 119 + 54 = 305 books
THERE WERE 7 GIRLS
There were 5
225 ÷ 3 = 75
75 × 9 = 675
75 × 3 = 225
- as more students increase so does the number of teddies
- there has to be a perfect mixture of boys and girls wherein 1/3 of them carry teddies that also carry books adding to 305 total
