Someone solve my math assignment

[Deleted member 56968]

A line goes through the point p(8,3) and has normal vector −2 , 3.

a. Determine an equation for the line l.
b. Determine the acute angle v between the line l and the x-axis.




please
@LancasteR @deadstock @MoggerGaston @AOL @nathan @paladincel_ @moredatesmorerapes @noobs @_MVP_ you guys are smart

 

[Deleted member 21182]

If anyone helps this faggot I will make it my mission to put u on every Jewish black list possible

 

[Deleted member 42399]

Nigga this shit is easy asf if u struggle just draw the coordinates to visualize it

or just ask chatgpt

 

[Deleted member 56968]

If anyone helps this faggot I will make it my mission to put u on every Jewish black list possible

Probably mad you can't solve it huh? Why dont you prove me wrong and solve it

 

[Deleted member 21182]

Probably mad you can't solve it huh? Why dont you prove me wrong and solve it

Ask ur mom faghot

 

[Deleted member 56968]

Nigga this shit is easy asf if u struggle just draw the coordinates to visualize it

or just ask chatgpt

No how do you make an equation for the point?

 

[Deleted member 56968]

Ask ur mom faghot

Well seems like you can't solve it.

 

[Nick.Harte]

If anyone helps this faggot I will make it my mission to put u on every Jewish black list possible

Can you explain why ?

 

[zaideas]

nigga this is cal1 and part 2 is literally a formula

 

[Deleted member 42399]

No how do you make an equation for the point?

something like f(x) = (value on y axis at x=0) + (gradient of the line) * y or so. I'm an oldcel

 

[AverageCurryEnjoyer]

nigga not passing jfl

 

[Deleted member 56968]

nigga this is cal1 and part 2 is literally a formula

already went above my head

 

[AverageCurryEnjoyer]

something like f(x) = (value on y axis at x=0) + (gradient of the line) * y or so. I'm an oldcel

y=mx+b

 

[Deleted member 21182]

Can you explain why ?

he can’t pass

 

[Deleted member 42399]

y=mx+b

what's m and b?

 

[Deleted member 56968]

something like f(x) = (value on y axis at x=0) + (gradient of the line) * y or so. I'm an oldcel

don't even know what youre talking about

 

[Deleted member 21182]

X=BBC to the maximum of y=BWC x 9

write that for a

 

[Lebgfinal]

Nobody should give op the answer because if he cant answer this he will fail at the exam

 

[AverageCurryEnjoyer]

what's m and b?

slope and y intercept

 

[Deleted member 42399]

slope and y intercept

So u just repeated what i said?

 

[Deleted member 56968]

Nobody should give op the answer because if he cant answer this he will fail at the exam

Already failed the oral exam

 

[Deleted member 21182]

Nobody should give op the answer because if he cant answer this he will fail at the exam

Yk what ur so annoying now I want op to get the answer

 

[AverageCurryEnjoyer]

So u just repeated what i said?

nah you made a tiny error when multiplying gradient to y not x. Also you might confuse this nigga if you put f(x)

 

[Deleted member 56968]

nah you made a tiny error when multiplying gradient to y not x. Also you might confuse this nigga if you put f(x)

Well you certainly seem smart why not give me the answer

 

[Deleted member 21182]

nah you made a tiny error when multiplying gradient to y not x. Also you might confuse this nigga if you put f(x)

So many nerdy high iq faggots in this forum

What happened to being a looksmax autist who only calculates vectors and angles if they are related to facial bones

 

[Deleted member 42399]

nah you made a tiny error when multiplying gradient to y not x. Also you might confuse this nigga if you put f(x)

U right

 

[AverageCurryEnjoyer]

Well you certainly seem smart why not give me the answer

fuck you mean common vector. Just assume the two points. Okay the question is wrong or The answer is Y=3 and Zero.

U right

Thanks bhai

So many nerdy high iq faggots in this forum

What happened to being a looksmax autist who only calculates vectors and angles if they are related to facial bones

Joined Aug 1, 2022, Posts 52,894, Reputation 71,633. It never began.

 

[Nick.Harte]

Where do you have to submit this ?

 

[Deleted member 56968]

fuck you mean common vector. Just assume the two points. Okay the question is wrong or The answer is Y=3 and Zero.

Thanks bhai

Joined Aug 1, 2022, Posts 52,894, Reputation 71,633. It never began.

U right

So many nerdy high iq faggots in this forum

What happened to being a looksmax autist who only calculates vectors and angles if they are related to facial bones

Nah i just solved it, it literally took 2 minutes you guys are stupid idk how you overcomplicate such a simple thing
-2(x-8)+3(y-3)=0

 

[Nick.Harte]

Nah i just solved it

Why did you ask then ?

 

[Deleted member 56968]

Where do you have to submit this ?

Why did you ask then ?

I was watching netflix and didn't wanna do anything

 

[_MVP_]

easy.

Let's solve this problem step by step.

Part (a): Determine the equation of the line.​

The general form of the equation of a line in two dimensions can be given as:

Ax+By=CAx + By = CAx+By=C
where (A,B)(A, B)(A,B) is the normal vector to the line.

Given the normal vector as (−2,3)(-2, 3)(−2,3), the equation of the line can be written as:

−2x+3y=C-2x + 3y = C−2x+3y=C
Next, to determine CCC, we can substitute the point P(8,3)P(8, 3)P(8,3) into the equation, since the line passes through this point.

Substituting x=8x = 8x=8 and y=3y = 3y=3:

−2(8)+3(3)=C-2(8) + 3(3) = C−2(8)+3(3)=C−16+9=C-16 + 9 = C−16+9=CC=−7C = -7C=−7
So, the equation of the line is:

−2x+3y=−7-2x + 3y = -7−2x+3y=−7
Alternatively, this can be rewritten in slope-intercept form:

2x−3y=7ory=23x−732x - 3y = 7 \quad \text{or} \quad y = \frac{2}{3}x - \frac{7}{3}2x−3y=7ory=32x−37

Part (b): Determine the acute angle vvv between the line and the x-axis.​

The slope of the line mmm is given by the ratio of the coefficients of xxx and yyy in the equation:

m=−AB=−(−2)3=23m = \frac{-A}{B} = \frac{-(-2)}{3} = \frac{2}{3}m=B−A=3−(−2)=32
The angle θ\thetaθ between the line and the x-axis is related to the slope by:

tan⁡(θ)=m\tan(\theta) = mtan(θ)=m
Substituting the value of mmm:

tan⁡(θ)=23\tan(\theta) = \frac{2}{3}tan(θ)=32
To find the acute angle θ\thetaθ, take the arctan:

θ=tan⁡−1(23)\theta = \tan^{-1}\left(\frac{2}{3}\right)θ=tan−1(32)
Calculating this:

θ≈33.69∘\theta \approx 33.69^\circθ≈33.69∘
Thus, the acute angle vvv between the line and the x-axis is approximately 33.69∘33.69^\circ33.69∘.

 

[Deleted member 56968]

easy.

Let's solve this problem step by step.

Part (a): Determine the equation of the line.​

The general form of the equation of a line in two dimensions can be given as:

Ax+By=CAx + By = CAx+By=C
where (A,B)(A, B)(A,B) is the normal vector to the line.

Given the normal vector as (−2,3)(-2, 3)(−2,3), the equation of the line can be written as:

−2x+3y=C-2x + 3y = C−2x+3y=C
Next, to determine CCC, we can substitute the point P(8,3)P(8, 3)P(8,3) into the equation, since the line passes through this point.

Substituting x=8x = 8x=8 and y=3y = 3y=3:

−2(8)+3(3)=C-2(8) + 3(3) = C−2(8)+3(3)=C−16+9=C-16 + 9 = C−16+9=CC=−7C = -7C=−7
So, the equation of the line is:

−2x+3y=−7-2x + 3y = -7−2x+3y=−7
Alternatively, this can be rewritten in slope-intercept form:

2x−3y=7ory=23x−732x - 3y = 7 \quad \text{or} \quad y = \frac{2}{3}x - \frac{7}{3}2x−3y=7ory=32x−37

Part (b): Determine the acute angle vvv between the line and the x-axis.​

The slope of the line mmm is given by the ratio of the coefficients of xxx and yyy in the equation:

m=−AB=−(−2)3=23m = \frac{-A}{B} = \frac{-(-2)}{3} = \frac{2}{3}m=B−A=3−(−2)=32
The angle θ\thetaθ between the line and the x-axis is related to the slope by:

tan⁡(θ)=m\tan(\theta) = mtan(θ)=m
Substituting the value of mmm:

tan⁡(θ)=23\tan(\theta) = \frac{2}{3}tan(θ)=32
To find the acute angle θ\thetaθ, take the arctan:

θ=tan⁡−1(23)\theta = \tan^{-1}\left(\frac{2}{3}\right)θ=tan−1(32)
Calculating this:

θ≈33.69∘\theta \approx 33.69^\circθ≈33.69∘
Thus, the acute angle vvv between the line and the x-axis is approximately 33.69∘33.69^\circ33.69∘.

What the fuck is this? My teacher will think im crazy if i give him this. is this chatgpt?

 

[Deleted member 88079]

Im lowiq af

 

[Deleted member 56968]

fuck you mean common vector. Just assume the two points. Okay the question is wrong or The answer is Y=3 and Zero.

y=3? you used chatgpt

 

[Deleted member 17578]

42

 

[AverageCurryEnjoyer]

y=3? you used chatgpt

nah, just assumed the vector was a mistake on your behalf

 

[Deleted member 56968]

nah, just assumed the vector was a mistake on your behalf

sure buddy