3, 14, 42, 104, ?

[Deleted member 16275]

4368

 

[Chinacurry]

3, 14, 42, 104, ?

~110 iq sequence

tagging some forum nerds

@cloUder @OGJBSLAYER @JackTheKnife @the BULL

Seems there's more than one way, given u made it up, but if we assume 3 is zero, then u can do double the last difference plus 6.

So 234?

 

[mogger123]

This is what I did:

3 -- +11 --> 14 -- +28 --> 42 -- + 62 --> 104

11
28 = 11*2 +6
62 = 28*2 + 6 then

62*2 +6 = 130 and 104 + 130 = 234

You can probably find other patterns that give the same answer or different answers. I believe the whole point of these questions is to test whether the person has basic arithmetic skills and can see patterns. I guess most low-IQ people freeze with these types of questions so if you put several of them under a time constraint you can estimate their IQ.

But where does the initial 3 and 11 come from? This is a very unsatisfying ad hoc "solution"

 

[mogger123]

It doesn't. Maybe cuz you already visited the place

Nope, it definitely comes up. You are just Google noob

 

[Dr. Bludy]

Its ROPING TIME

 

[Myth]

ITT Pseudo intellects try to act smart instead of using this profound knowledge they posses for anything remotely useful.

 

[Deleted member 23558]

but there's no pattern because random primes are being used each time with addition and subtraction being chosen arbitarirly (plus as someone else mentioned 1 isnt prime)

270 is the right answer btw, i wanted to see how you got that

Difference between the numbers 3 and 14 is 11
14 and 42 is 28 and 42 and 104 is 62

11= 3^2+2
28= 5^2+3
62=8^2-2
X= Y^2-3 ( order on the rhs is + 2 + 3 -2 and therefore -3 on the last term)

Y= 13 as 2+3= 5 and 5+3=8 ( Fibonacci sequence)

X= 166

Adding 166 to 104 = 270

 

[mogger123]

Difference between the numbers 3 and 14 is 11
14 and 42 is 28 and 42 and 104 is 62

11= 3^2+2
28= 5^2+3
62=8^2-2
X= Y^2-3 ( order on the rhs is + 2 + 3 -2 and therefore -3 on the last term)

Y= 13 as 2+3= 5 and 5+3=8 ( Fibonacci sequence)

X= 166

Adding 166 to 104 = 270

prime examle of why options arent provided

you have arrived at the correct answer through some random autism that amkes absolutely no sense and does not constitute a pattern

 

[5.5psl]

Thanks for wasting my 5 minutes for this dumbass question

 

[Deleted member 26633]

this is 80 iq question. if you cant instantly see it ur retarded. i was about to solve it for you but its literally so easy its humiliating

Spoiler

234

 

[Deleted member 23558]

prime examle of why options arent provided

you have arrived at the correct answer through some random autism that amkes absolutely no sense and does not constitute a pattern

Na you just don’t understand it lol even if I explain like to a 5 yo you’ll keep saying it’s random schizophrenic bla bla so peace

 

[Deleted member 23558]

Thanks for wasting my 5 minutes for this dumbass question

Y the Jfl this is basic AP taught in 8 th grade

 

[mogger123]

Na you just don’t understand it lol even if I explain like to a 5 yo you’ll keep saying it’s random schizophrenic bla bla so peace

why is the first term 3?

assuming fibonacci from three terms is a huge stretch

wtf is the sequences 2,3,-2,-3?

 

[5.5psl]

Y the Jfl this is basic AP taught in 8 th grade

Bruh that's not ap
Ap goes like this : 2,4,6,8,10
When there's a common diffrence and it repeats itself and that's not even a gp
That's just ridiculous dumbass question tbh

 

[mogger123]

Bruh that's not ap
Ap goes like this : 2,4,6,8,10
When there's a common diffrence and it repeats itself and that's not even a gp
That's just ridiculous dumbass question tbh

your just mad your not high enough iq to solve

 

[Deleted member 23558]

why is the first term 3?

Because that’s the number we start from in the sequence to get 11 . It is just AP - there’s no requirement for Fibonacci to start from 1 or 0 . Some patterns even go deep into the sequence as it’s an infinite series.

wtf is the sequences 2,3,-2,-3?

The additive /subtractive terms on the rhs. The first equation it’s +2 the second it’s 3 the third we substract 2 and so the fourth we subtract 3 to maintain symmetry

 

[Deleted member 23558]

Bruh that's not ap
Ap goes like this : 2,4,6,8,10
When there's a common diffrence and it repeats itself and that's not even a gp
That's just ridiculous dumbass question tbh

Well yeah d remains the same in Ap but what I meant was it is the same logic you find out the difference in the series that keeps increasing ( so more like a series than Ap) and you find a pattern amongst them rather than the main terms . Since there is no obvious pattern among the terms 3 14 42 104 in themselves.

 

[Deleted member 23558]

this is 80 iq question. if you cant instantly see it ur retarded. i was about to solve it for you but its literally so easy its humiliating

Spoiler

234

One guy explained reasoning for 234 it answers only two terms doesn’t explain the term 11 in the rhs in the first

 

[mogger123]

Because that’s the number we start from in the sequence to get 11 . It is just AP - there’s no requirement for Fibonacci to start from 1 or 0 . Some patterns even go deep into the sequence as it’s an infinite series.


The additive /subtractive terms on the rhs. The first equation it’s +2 the second it’s 3 the third we substract 2 and so the fourth we subtract 3 to maintain symmetry

bro stop talking to me like im 5. i have a more in depth math education than you.

your "pattern" is retarded, stop coping

 

[Deleted member 21898]

This is absolutely useless for survival and reproduction

 

[mogger123]

This is absolutely useless for survival and reproduction

i dont remember asking for you to speak, tbh

 

[Deleted member 23558]

bro stop talking to me like im 5. i have a more in depth math education than you.

your "pattern" is retarded, stop coping

Caged

 

[Deleted member 21898]

i dont remember asking for you to speak, tbh

I don't remember asking you to make this thread, tbh. Why are you being hostile man? I'm just joking, chill. I was being sarcastic.

 

[Deleted member 16275]

 

[Deleted member 26633]

One guy explained reasoning for 234 it answers only two terms doesn’t explain the term 11 in the rhs in the first

define sequence a( n ) as 11 *n + (6* (n-1))
the sequence members are as follows: 11, 28, 62, ...
choose arbitrary starting natural number, in this case, 3
for every next member ,add the previous and the appropriate sequence member
3, 3 + (11*1)+0 = 14, 14 +(11*2) +6 *1 = 42, ...
you are all midwits.

 

[Deleted member 23558]

define sequence a( n ) as 11 *n + (6* (n-1))
the sequence members are as follows: 11, 28, 62, ...
choose arbitrary starting natural number, in this case, 3
for every next member ,add the previous and the appropriate sequence member
3, 3 + (11*1)+0 = 14, 14 +(11*2) +6 *1 = 42, ...
you are all midwits.

Just define sequence theory. You’re the midwit you dumb mong when there’s no reasoning behind why you’re defining that particular sequence when you cannot even explain the first term 11. You’re in effect onlu explaining two terms the 28 one and 62 one. Many others in the thread got the same answer as you go look.. all you’re doing is defining a function that makes the first term 11 by using the term n-1. Proper midwit move skim the thread first. And even the sequence you defined doesn’t work clearly as the third term is 45 a number nowhere to be found in the sequence. The answer is 270 as I posted and mogger123 verified but said I arrived at it randomly because he’s too low iq to understand the Fibonacci sequence and symmetry.

 

[Deleted member 26633]

Just define sequence theory. You’re the midwit you dumb mong when there’s no reasoning behind why you’re defining that particular sequence when you cannot even explain the first term 11. You’re in effect onlu explaining two terms the 28 one and 62 one. Many others in the thread got the same answer as you go look.. all you’re doing is defining a function that makes the first term 11 by using the term n-1. Proper midwit move skim the thread first. And even the sequence you defined doesn’t work clearly as the third term is 45 a number nowhere to be found in the sequence. The answer is 270 as I posted and mogger123 verified but said I arrived at it randomly because he’s too low iq to understand the Fibonacci sequence and symmetry.

the sequence perfectly defines the first term. although i have written it perhaps too hastly the proper definition would be a ( n ) = 11*n + K where K is a natural number defined as 0 when n = 1 and 6 when n > 1. it is mathematically completely correct and describes the given sequence if we do the steps i have provided.

 

[Deleted member 23558]

the sequence perfectly defines the first term. although i have written it perhaps too hastly the proper definition would be a ( n ) = 11*n + K where K is a natural number defined as 0 when n = 1 and 6 when n > 1. it is mathematically completely correct and describes the given sequence if we do the steps i have provided.

11*3+6=39

 

[Deleted member 26633]

11*3+6=39

you should use the sequence with the rule ive given for the arbitrary one that starts with 3. defined rigorously, the original sequence is actually a recursive one, a( n ) = 11 for n = 1 and a( n ) = 2 * a(n-1) + 6 for n > 1.

 

[mogger123]

define sequence a( n ) as 11 *n + (6* (n-1))
the sequence members are as follows: 11, 28, 62, ...
choose arbitrary starting natural number, in this case, 3
for every next member ,add the previous and the appropriate sequence member
3, 3 + (11*1)+0 = 14, 14 +(11*2) +6 *1 = 42, ...
you are all midwits.

midwit alert

11*3+6*2 = 45 not 62

 

[Deleted member 23558]

you should use the sequence with the rule ive given for the arbitrary one that starts with 3. defined rigorously, the original sequence is actually a recursive one, a( n ) = 11 for n = 1 and a( n ) = 2 * a(n-1) + 6 for n > 1.

Ok but my original criticism remains. You are in effect only explaining two terms with the second defined fn. The first function is far too arbitrary. My pattern explains all three terms .

 

[kovacs]

Ok but my original criticism remains. You are in effect only explaining two terms with the second defined fn. The first function is far too arbitrary. My pattern explains all three terms .

brahmin i talked to you like months ago about using dnp for fat loss. i ended up just using ostarine and cardarine and dropped fat precipitiously.

why havent your efforts worked out? you seemed very determined at the time.

3, 14, 42, 104, ?

~110 iq sequence

tagging some forum nerds

@cloUder @OGJBSLAYER @JackTheKnife @the BULL

cant get the pattern in a non-contrived manner sadly. but miring how the forum pseuds can't help but scurry to your threads like rats.

 

[Deleted member 23558]

brahmin i talked to you like months ago about using dnp for fat loss. i ended up just using ostarine and cardarine and dropped fat precipitiously.

why havent your efforts worked out? you seemed very determined at the time.

cant get the pattern in a non-contrived manner sadly. but miring how the forum pseuds can't help but scurry to your threads like rats.

check my other threads. i got in a psych ward and was prescribed meds that made me put on weight. my dnp was also seized by police. im off them all now tho and dropping around .75 kg a week nowadays.

 

[Deleted member 26633]

ending the thread with a complete, rigorous, mathematically complete solution, taking into account all previous given solutions:
Define sequence a ( n ) as fib ( n ) ^ 2 + b ( n ) where fib ( n ) is nth element of fibonacci sequence and b ( n ) is nth element of the sequence
+2 , +3, -2, +2, +3, -2, ....
thus, the elements of the sequence a ( n ) are as follows:
1^2 + 2 = 3
1^2 + 3 = 4
2^2 - 2 = 2
3^2 + 2 = 11
5^2 + 3 = 28
8^2 -2 = 62
13^2 + 2 = 171

Now, define a sequence c = a(1) when n = 1, and c = c(n-1) + a(n+4), where a(n+4) is sequence a starting from the 4th member. the given sequence is now formed:
3, 3+11 = 14, 14 + 28 = 42, 42 + 62 = 104, 104 +171 = 275

 

[mogger123]

ending the thread with a complete, rigorous, mathematically complete solution, taking into account all previous given solutions:
Define sequence a ( n ) as fib ( n ) ^ 2 + b ( n ) where fib ( n ) is nth element of fibonacci sequence and b ( n ) is nth element of the sequence
+2 , +3, -2, +2, +3, -2, ....
thus, the elements of the sequence a ( n ) are as follows:
1^2 + 2 = 3
1^2 + 3 = 4
2^2 - 2 = 2
3^2 + 2 = 11
5^2 + 3 = 28
8^2 -2 = 62
13^2 + 2 = 171

Now, define a sequence c = a(1) when n = 1, and c = c(n-1) + a(n+4), where a(n+4) is sequence a starting from the 4th member. the given sequence is now formed:
3, 3+11 = 14, 14 + 28 = 42, 42 + 62 = 104, 104 +171 = 275

nope

it's much much much simpler than this

 

[mogger123]

hint: the sequence is not recursively defined. think about why it starts with 3

 

[Deleted member 26633]

nope

it's much much much simpler than this

it isnt a matter of yes or no, given that you didnt provide options, this answer completely describes the given sequence and is a valid next element

 

[mogger123]

it isnt a matter of yes or no, given that you didnt provide options, this answer completely describes the given sequence and is a valid next element

yes it is

or i could just say it's the seaquence h[n] where h[1]=3, h[2]=14, h[3]=42, h[4]=104 and h[5]=tbhiorvfnfjlknrefvnk

 

[JackTheKnife]

@Vermilioncore What are your thoughts?

 

[Deleted member 26633]

yes it is

or i could just say it's the seaquence h[n] where h[1]=3, h[2]=14, h[3]=42, h[4]=104 and h[5]=tbhiorvfnfjlknrefvnk

exactly ,that is how sequences work, it is completely uncertain what the next element can be if you dont know the general member. for example, even if you gave me a sequence 0,0,0 and told me to find next element, if i said its it is -6 would be correct, if the sequence was defined as (3-n)(2-n)(1-n)

 

[mogger123]

exactly ,that is how sequences work, it is completely uncertain what the next element can be if you dont know the general member. for example, even if you gave me a sequence 0,0,0 and told me to find next element, if i said its it is -6 would be correct, if the sequence was defined as (3-n)(2-n)(1-n)

exactly, so the simplest solution is the correct one. i.e not yours

 

[JackTheKnife]

exactly ,that is how sequences work, it is completely uncertain what the next element can be if you dont know the general member. for example, even if you gave me a sequence 0,0,0 and told me to find next element, if i said its it is -6 would be correct, if the sequence was defined as (3-n)(2-n)(1-n)

You defeated mogger123?

 

[mogger123]

exactly ,that is how sequences work, it is completely uncertain what the next element can be if you dont know the general member. for example, even if you gave me a sequence 0,0,0 and told me to find next element, if i said its it is -6 would be correct, if the sequence was defined as (3-n)(2-n)(1-n)

for example 1, 4, 9, 16, ?

the correct answer is 25 even though you could find other contrived "answers"

 

[Deleted member 27561]

Just type in random numbers, say there's an IQ requirement for solving it, and watch forum autists flood your post theory

 

[JackTheKnife]

for example 1, 4, 9, 16, ?

the correct answer is 25 even though you could find other contrived "answers"

Yo solve this one for me: Straight, Gay, ?

 

[Deleted member 26633]

for example 1, 4, 9, 16, ?

the correct answer is 25 even though you could find other contrived "answers"

the answer by definition is correct if it is a next member of a sequence whose preceding members are the ones provided. this is the exact reason why most tests offer solutions, so people dont come with hacky solutions

 

[JackTheKnife]

Just type in random numbers, say there's an IQ requirement for solving it, and watch forum autists flood your post theory

Cope, users provided interesting answers. You're too low IQ to even begin solving any of this. Sit yo ass on the retard bench and watch

 

[Deleted member 23558]

ending the thread with a complete, rigorous, mathematically complete solution, taking into account all previous given solutions:
Define sequence a ( n ) as fib ( n ) ^ 2 + b ( n ) where fib ( n ) is nth element of fibonacci sequence and b ( n ) is nth element of the sequence
+2 , +3, -2, +2, +3, -2, ....
thus, the elements of the sequence a ( n ) are as follows:
1^2 + 2 = 3
1^2 + 3 = 4
2^2 - 2 = 2
3^2 + 2 = 11
5^2 + 3 = 28
8^2 -2 = 62
13^2 + 2 = 171

Now, define a sequence c = a(1) when n = 1, and c = c(n-1) + a(n+4), where a(n+4) is sequence a starting from the 4th member. the given sequence is now formed:
3, 3+11 = 14, 14 + 28 = 42, 42 + 62 = 104, 104 +171 = 275

youre on the right track bring in symmetry and you are done.

 

[Deleted member 27561]

Cope, users provided interesting answers. You're too low IQ to even begin solving any of this. Sit yo ass on the retard bench and watch

Post degree + GPA?

 

[Deleted member 23558]

Difference between the numbers 3 and 14 is 11
14 and 42 is 28 and 42 and 104 is 62

11= 3^2+2
28= 5^2+3
62=8^2-2
X= Y^2-3 ( order on the rhs is + 2 + 3 -2 and therefore -3 on the last term)

Y= 13 as 2+3= 5 and 5+3=8 ( Fibonacci sequence)

X= 166

Adding 166 to 104 = 270

@JackTheKnife @QQ442244