If ur high IQ answer this logic question

[Gaygymmaxx]

There are three gods: A, B, and C.

• One always tells the truth (True).
• One always lies (False).
• One answers randomly (Random) — on each question he flips a fair coin to decide whether to answer truthfully or lie.

Each god answers only “da” or “ja” (you do not know which word means “yes” and which means “no”).


You may ask exactly three yes/no questions total.


Each question must be asked to a single god (you may choose which god for each question, and you may ask the same god more than once).


Your task: determine which god is True, which is False, and which is Random.





Constraints to note (important):

• You don’t know whether “da” = yes or “ja” = yes.
• Random’s answer is independent each time (a fair coin decides whether he answers truthfully or falsely on that question).
• Questions must be answerable by yes/no (i.e., framed so a truthful/lying god can respond with yes/no).

Tbh it’s not actually that hard but it requires advanced problem solving skills for sure. For refernce I got the answer in under 2-3 mins, so defo no impossible

You can chose the god? Blud either this is stupid easy or I'm stupid

You ask the Lie God if the A^2 + B^2 = C^2

The answer he gives means no because he always lies, the other answer is yes

You only need 1 question no?

 

[Gaygymmaxx]

You can chose the god? Blud either this is stupid easy or I'm stupid

You ask the Lie God if the A^2 + B^2 = C^2

The answer he gives means no because he always lies, the other answer is yes

You only need 1 question no?

Wait I dnrd properly

But still, if you can choose the god what even is the point of asking questions

 

[CantStopTheMog]

You can chose the god? Blud either this is stupid easy or I'm stupid

You ask the Lie God if the A^2 + B^2 = C^2

The answer he gives means no because he always lies, the other answer is yes

You only need 1 question no?

Nope u don’t know which god is which

 

[CantStopTheMog]

Wait I dnrd properly

But still, if you can choose the god what even is the point of asking questions

U can’t

 

[jeremyy]

I haven’t got one answer lmao but had like 15 viewers brutal Iq pill. This is a common Iq question lmao even sub130 can answer this

Claimed high Iq users:
@imontheloose @Gaygymmaxx @thales20 @anthony111553 @Never Get Up

everyone there is retarded except for last guy

 

[CantStopTheMog]

everyone there is retarded except for last guy

Imontheloose is a literal Oxford university graduate and GGM has very high IQ takes, Anthony claims high IQ and Thales is Js Thales but bever get up is probs the most retarded of them all

 

[william.]

There are three gods: A, B, and C.

• One always tells the truth (True).
• One always lies (False).
• One answers randomly (Random) — on each question he flips a fair coin to decide whether to answer truthfully or lie.

Each god answers only “da” or “ja” (you do not know which word means “yes” and which means “no”).


You may ask exactly three yes/no questions total.


Each question must be asked to a single god (you may choose which god for each question, and you may ask the same god more than once).


Your task: determine which god is True, which is False, and which is Random.





Constraints to note (important):

• You don’t know whether “da” = yes or “ja” = yes.
• Random’s answer is independent each time (a fair coin decides whether he answers truthfully or falsely on that question).
• Questions must be answerable by yes/no (i.e., framed so a truthful/lying god can respond with yes/no).

Tbh it’s not actually that hard but it requires advanced problem solving skills for sure. For refernce I got the answer in under 2-3 mins, so defo no impossible

im low iq

 

[CantStopTheMog]

im low iq

Dw it’s a quite hard question

 

[mrdouchebag]

I asked Grok 4, that has over 9000 IQ, and I got the answer. It's a retarded answer just as I expected.
I am eager to see your simpler quicker way to solve this. You claimed you found a loophole.

 

[william.]

Dw it’s a quite hard question

can you explain?

 

[CantStopTheMog]

I asked Grok 4, that has over 9000 IQ, and I got the answer. It's a retarded answer just as I expected.
I am eager to see your simpler quicker way to solve this. You claimed you found a loophole.

any god can be any letter is 1 answer although a cheat answer as it involves 0 problem solving and is just an attack on question

Well, of course not a one solution only, but a solution.

I’ll elaborate on why it would work AFAIK.

To A: “If I asked you ‘is B random?’ would you say ‘da’?” If A says “da”, the non-random God must be C. If A says “ja”, the non-random God must be B.

To whichever non-random God was right after that question, let’s call it D as a label: “if I asked you ‘are you true?’ would you say ‘da’?” If D says “da”, D is true. If D says “ja”, D is false.

Then you can simply ask D again, “if I asked you, ‘is A random?’ would you say ‘da’?” Then if D says “da”, A is random. If D says “ja”, A is not random.

How does this logic chain not work?

In easier terms, if u find the random god it is easy from there. Because u will know what either Ja or Da means, and can therefore determine the other 2. This is because ur asking an IF statement/question. So no matter if it is true or false god answer applies because the words have no meaning as of when asked.

answer.

 

[CantStopTheMog]

can you explain?

Read reply above this one

 

[Noesis]

I'll gamble my chances

 

[william.]

its not possible

 

[CantStopTheMog]

its not possible

Why

 

[william.]

Well, of course not a one solution only, but a solution.

I’ll elaborate on why it would work AFAIK.

To A: “If I asked you ‘is B random?’ would you say ‘da’?” If A says “da”, the non-random God must be C. If A says “ja”, the non-random God must be B.

To whichever non-random God was right after that question, let’s call it D as a label: “if I asked you ‘are you true?’ would you say ‘da’?” If D says “da”, D is true. If D says “ja”, D is false.

Then you can simply ask D again, “if I asked you, ‘is A random?’ would you say ‘da’?” Then if D says “da”, A is random. If D says “ja”, A is not random.

How does this logic chain not work?

this is chatgpt

 

[CantStopTheMog]

this is chatgpt

Doesn’t look like AI writing. Either way it’s the method I used so there is all the chance he worked it out too

 

[william.]

Well, of course not a one solution only, but a solution.

I’ll elaborate on why it would work AFAIK.

To A: “If I asked you ‘is B random?’ would you say ‘da’?” If A says “da”, the non-random God must be C. If A says “ja”, the non-random God must be B.

To whichever non-random God was right after that question, let’s call it D as a label: “if I asked you ‘are you true?’ would you say ‘da’?” If D says “da”, D is true. If D says “ja”, D is false.

Then you can simply ask D again, “if I asked you, ‘is A random?’ would you say ‘da’?” Then if D says “da”, A is random. If D says “ja”, A is not random.

How does this logic chain not work?

Doesn’t look like AI writing. Either way it’s the method I used so there is all the chance he worked it out too

i tried ai and he said the exact same thing

 

[mrdouchebag]

Grok's solution:​

Spoiler

Question 1: Ask god B, "If I asked you 'Is A the Random god?', would you say 'ja'?"​

• If B answers "ja," then C is guaranteed not to be Random (either A is Random and B is not, or B is Random). Proceed by asking Questions 2 and 3 to C.
• If B answers "da," then A is guaranteed not to be Random (either A is not Random and B is not, or B is Random). Proceed by asking Questions 2 and 3 to A.

(Let X denote the non-Random god identified above, either A or C.)

Question 2: Ask god X, "If I asked you 'Are you the False god?', would you say 'ja'?"​

• If X answers "ja," then X is False.
• If X answers "da," then X is True.

Question 3: Ask god X, "If I asked you 'Is B the Random god?', would you say 'ja'?"​

• If X answers "ja," then B is Random (and the remaining god is the opposite type of X: True if X is False, or False if X is True).
• If X answers "da," then B is not Random (so the remaining god is Random, and B is the opposite type of X: True if X is False, or False if X is True).

This determines all identities by elimination in every possible scenario.

 

[CantStopTheMog]

i tried ai and he said the exact same thing

Oh maybe it was AI his answer who knows.
I still believe him that he worked it out, it’s not that hard

 

[CantStopTheMog]

Grok's solution:​

Spoiler

Question 1: Ask god B, "If I asked you 'Is A the Random god?', would you say 'ja'?"​

• If B answers "ja," then C is guaranteed not to be Random (either A is Random and B is not, or B is Random). Proceed by asking Questions 2 and 3 to C.
• If B answers "da," then A is guaranteed not to be Random (either A is not Random and B is not, or B is Random). Proceed by asking Questions 2 and 3 to A.

(Let X denote the non-Random god identified above, either A or C.)

Question 2: Ask god X, "If I asked you 'Are you the False god?', would you say 'ja'?"​

• If X answers "ja," then X is False.
• If X answers "da," then X is True.

Question 3: Ask god X, "If I asked you 'Is B the Random god?', would you say 'ja'?"​

• If X answers "ja," then B is Random (and the remaining god is the opposite type of X: True if X is False, or False if X is True).
• If X answers "da," then B is not Random (so the remaining god is Random, and B is the opposite type of X: True if X is False, or False if X is True).

This determines all identities by elimination in every possible scenario.

Basically the same as me and imontheloose then.
it doesn’t take long tbh, u just have to ask an if question to determine the random and then u can do either god after with same questions and check ur reasoning in 3rd question. So almost the same as my method

 

[imontheloose]

this is chatgpt

This is one of the most infamous logic chains there is in triplet reasoning. You study something almost identical to this in any advanced probability class. If a LLM told you the same method as I did to solve x^2 - 4 = 0, would you say it’s also ChatGPT?

 

[CantStopTheMog]

This is one of the most infamous logic chains there is in triplet reasoning. You study something almost identical to this in any advanced probability class. If an LLM told you the same method as I did to solve x^2 - 4 = 0, would you say it’s also ChatGPT?

I learned the method from my probability class technically speaking although I only put 2 and 2 together after reading this reply so yes I believe u

 

[imontheloose]

I learned the method from my probability class technically speaking although I only put 2 and 2 together after reading this reply so yes I believe u

It’s common in probability classes to teach you these weird logic chains. There’s a systematic way to solve them hence why every single LLM will give you the same sort of chain because there is a method to solve it. Some people don’t understand how it works, however, so when they see it solved, they immediately blame it on the robot that can also solve it. Lol.

 

[CantStopTheMog]

It’s common in probability classes to teach you these weird logic chains. There’s a systematic way to solve them hence why every single LLM will give you the same sort of chain because there is a method to solve it. Some people don’t understand how it works, however, so when they see it solved, they immediately blame it on the robot that can also solve it. Lol.

I originally looked at this problem as a more of a 2 step per question solution which it is by adding an “if” but u can also solve the exact same way with logic and probability Chains it’s seriously not that hard of a question in all reality

 

[.Cx]

I originally looked at this problem as a more of a 2 step per question solution which it is by adding an “if” but u can also solve the exact same way with logic and probability Chains it’s seriously not that hard of a question in all reality

So I was right lol.
Nice question though, post more of them.

 

[william.]

Well, of course not a one solution only, but a solution.

I’ll elaborate on why it would work AFAIK.

To A: “If I asked you ‘is B random?’ would you say ‘da’?” If A says “da”, the non-random God must be C.

Why? what if a is random?

If A says “ja”, the non-random God must be B.

Why?

To whichever non-random God was right after that question, let’s call it D as a label: “if I asked you ‘are you true?’ would you say ‘da’?” If D says “da”, D is true. If D says “ja”, D is false.

Then you can simply ask D again, “if I asked you, ‘is A random?’ would you say ‘da’?” Then if D says “da”, A is random. If D says “ja”, A is not random.

How does this logic chain not work?

not Criticising btw, I just dont understand, and i dont think its possible with only three questions

 

[imontheloose]

I originally looked at this problem as a more of a 2 step per question solution which it is by adding an “if” but u can also solve the exact same way with logic and probability Chains it’s seriously not that hard of a question in all reality

The premise I mentioned here:

Cool exercise. Why not just do a repetition of “if I asked you X, would you say ‘da’?”

If X, then it will return “da” and “ja” if false no matter whether you’re asking true/false or “da” = yes/no. The wrapper of “if i asked you” basically cancels out lying vs. truthful. I can elaborate if necessary.

Is where you should actually focus on. That is the systematic way we were taught to handle unknowns like this (obviously replacing “da” and “ja” with other variables).

 

[CantStopTheMog]

So I was right lol.
Nice question though, post more of them.

Bro u weren’t right as u assumed which u were talking to first. Maybe u phrased ur answer wrongly but what u wrote isn’t correct. Good attempt tho and I can see ur reasoning
Yes I’ll post more

 

[CantStopTheMog]

The premise I mentioned here:

Is where you should actually focus on. That is the systematic way we were taught to handle unknowns like this (obviously replacing “da” and “ja” with other variables).

Oh I didn’t see ur first sentence here lol
either way we have virtually the same method

 

[william.]

Why? what if a is random?


Why?




not Criticising btw, I just dont understand, and i dont think its possible with only three questions

@CantStopTheMog answer ?

 

[CantStopTheMog]

Why? what if a is random?


Why?




not Criticising btw, I just dont understand, and i dont think its possible with only three questions

@imontheloose

 

[CantStopTheMog]

@CantStopTheMog answer ?

Why would I answer this when I’m not the one saying it and it’s @imontheloose ’s justification

 

[william.]

Why would I answer this when I’m not the one saying it and it’s @imontheloose ’s justification

U said u came to the same answer/methode

 

[CantStopTheMog]

U said u came to the same answer/methode

Same answer , somewhat different methods.
I mean I can explain his answer in all honesty I just can’t be bothered.
Everything relating to his solution I’ve covered in previous replies

 

[Gaygymmaxx]

U can’t

Ask C, to say "yes", if both had the same answer, and "no" if both had different answers

If C is either truth or lie God then they simply can't answer, so we can eliminate them (don't hate the player dog hate the game )

Ask A if blue the best color

Ask B if the sky is blue

Absolutely ruining your game but here's my logic

If C DOES answer, it is the random god
Therefore A will also not answer because it's subjective reguardless of yes or no

Then I just have to decide whether B is lying or telling the truth

If C doesn't answer, it is true or false god, then

A will either not answer, if it's also either true or false, and it will answer if it's the random god,

If its also the true or false god I'm cooked blud

But if A answers then its the random god,

Then I simply ask B is the sky is blue

So I have 75% chance of being right/figuring out the order

I'm cooked bro i spent too much time to not figure it out

I think I could solve it from here properly if I put a bit more effort in it's been like 40 minutes and I'm sitting in my car rn bro

 

[imontheloose]

Why? what if a is random?

So, it’s quite a cool trick in reality, we don’t really appreciate it, but my initial post mentions my key intuition I remember being told about.

Before I get into it, you need to really understand this wrapper lest it breaks your skull. That key premise is mentioned of, “If I asked you X, would you say Y?” If the god is not random, then the answer to the wrap is Y iff (if and only, sorry we use that a lot in maths…) P is true! Now that’s regardless which is yes or no and whether the god is a fibber or not. The wrap of “if I asked you…” cancels that out.

Now, D is guaranteed to be non-random after my first question even if A is random because if we take the case of A being random, then by the puzzle’s setup, B and C are non-random. A’s answer is just a coin flip but either branch is non-random therefore D is non-random, so that first Q1 is random-safe if you will.

Why?

Let’s just do another case review. Imagine A is not random. By the actual lemma, A’s answer to my wrapped Q is going to be “da” if and only (iff but I don’t want to confuse you) “B is random“ is true, or “ja” if and only “B is random” is false. Therefore if A says “da”, B is now determined to be random, the non-randoms have to be A and C. If A says “ja”, however, B is not random now, so B is either a truth-teller or a fibber. That’s the exact justification.

IDK how well I can explain this via text, but perhaps numbers help you better. Since this is logic at the end of the day, this can easily be extrapolated to numbers and maybe you’ll get it then? This should be enough an explanation, however.

 

[CantStopTheMog]

Ask C, to say "yes", if both had the same answer, and "no" if both had different answers

If C is either truth or lie God then they simply can't answer, so we can eliminate them (don't hate the player dog hate the game )

Ask A if blue the best color

Ask B if the sky is blue

Absolutely ruining your game but here's my logic

If C DOES answer, it is the random god
Therefore A will also not answer because it's subjective reguardless of yes or no

Then I just have to decide whether B is lying or telling the truth

If C doesn't answer, it is true or false god, then

A will either not answer, if it's also either true or false, and it will answer if it's the random god,

If its also the true or false god I'm cooked blud

But if A answers then its the random god,

Then I simply ask B is the sky is blue

So I have 75% chance of being right/figuring out the order

I'm cooked bro i spent too much time to not figure it out

I think I could solve it from here properly if I put a bit more effort in it's been like 40 minutes and I'm sitting in my car rn bro

Bro I mean u kinda broke the system lowkey but obv not correct. Good thinking tho, high IQ answer thinking outside the box. Also the 4 things u sent “aren’t available in my region”

what was this lol

 

[Gaygymmaxx]

Bro I mean u kinda broke the system lowkey but obv not correct. Good thinking tho, high IQ answer thinking outside the box. Also the 4 things u sent “aren’t available in my region” View attachment 4163185what was this lol

 

[CantStopTheMog]

Ask C, to say "yes", if both had the same answer, and "no" if both had different answers

If C is either truth or lie God then they simply can't answer, so we can eliminate them (don't hate the player dog hate the game )

Ask A if blue the best color

Ask B if the sky is blue

Absolutely ruining your game but here's my logic

If C DOES answer, it is the random god
Therefore A will also not answer because it's subjective reguardless of yes or no

Then I just have to decide whether B is lying or telling the truth

If C doesn't answer, it is true or false god, then

A will either not answer, if it's also either true or false, and it will answer if it's the random god,

If its also the true or false god I'm cooked blud

But if A answers then its the random god,

Then I simply ask B is the sky is blue

So I have 75% chance of being right/figuring out the order

I'm cooked bro i spent too much time to not figure it out

I think I could solve it from here properly if I put a bit more effort in it's been like 40 minutes and I'm sitting in my car rn bro

Just realised subjective questions wouldn’t work due to the true or false only contraint

 

[CantStopTheMog]

View attachment 4163189

Brutal UK dictatorship censoring anything remotely bad

 

[Gaygymmaxx]

Really pushing my brainpower bro I'm sad I didn't get it but I just smoked so I can't try again

Tag and make more this is fye

 

[mrdouchebag]

Second Grok answer:

Spoiler

Question 1: Ask god A, "Does 'da' mean 'yes' if and only if you are True if and only if B is Random?"​

• This complex nesting of biconditionals ensures that True and False will answer in a way that reveals information about B or C, while Random's unpredictability is accounted for in the branching logic.
• If A answers "da," then C is not Random (C is either True or False).
• If A answers "ja," then B is not Random (B is either True or False).

(Let X denote the non-Random god identified above, either B or C.)

Question 2: Ask god X, "Does 'da' mean 'yes' if and only if Pluto is a dwarf planet?"​

• This uses a known true fact (Pluto is classified as a dwarf planet) to simultaneously determine the meaning of "da"/"ja" and whether X is True or False.
• If X answers "da," then "da" means "yes," and X is True (since True affirms the true statement correctly).
• If X answers "ja," then "da" means "no," and X is True (since True would affirm by saying the word for "yes," which is "ja" in this case).
• If X answers in a way that contradicts (e.g., saying the word for "no" to a true statement), then X is False.

(Note: The exact interpretation resolves both language and type because False would lie about the fact, forcing a mismatch that identifies them.)

Question 3: Ask god X (now knowing their type and the language meanings), "Does 'da' mean 'yes' if and only if A is Random?"​

• With the language decoded and X's type known, their answer directly reveals if A is Random (adjusting for if X is False, who lies).
• This identifies A, and by elimination, determines B and C's roles.

This method succeeds in all cases by leveraging logic that "explodes" paradoxes for Random in certain scenarios, ensuring reliable branching.

 

[Gaygymmaxx]

Brutal UK dictatorship censoring anything remotely bad

No thoughts of self harm goy, we need slave labor from you!

Just put the fries in the bag

 

[Gaygymmaxx]

Second Grok answer:

Spoiler

Question 1: Ask god A, "Does 'da' mean 'yes' if and only if you are True if and only if B is Random?"​

• This complex nesting of biconditionals ensures that True and False will answer in a way that reveals information about B or C, while Random's unpredictability is accounted for in the branching logic.
• If A answers "da," then C is not Random (C is either True or False).
• If A answers "ja," then B is not Random (B is either True or False).

(Let X denote the non-Random god identified above, either B or C.)

Question 2: Ask god X, "Does 'da' mean 'yes' if and only if Pluto is a dwarf planet?"​

• This uses a known true fact (Pluto is classified as a dwarf planet) to simultaneously determine the meaning of "da"/"ja" and whether X is True or False.
• If X answers "da," then "da" means "yes," and X is True (since True affirms the true statement correctly).
• If X answers "ja," then "da" means "no," and X is True (since True would affirm by saying the word for "yes," which is "ja" in this case).
• If X answers in a way that contradicts (e.g., saying the word for "no" to a true statement), then X is False.

(Note: The exact interpretation resolves both language and type because False would lie about the fact, forcing a mismatch that identifies them.)

Question 3: Ask god X (now knowing their type and the language meanings), "Does 'da' mean 'yes' if and only if A is Random?"​

• With the language decoded and X's type known, their answer directly reveals if A is Random (adjusting for if X is False, who lies).
• This identifies A, and by elimination, determines B and C's roles.

This method succeeds in all cases by leveraging logic that "explodes" paradoxes for Random in certain scenarios, ensuring reliable branching.

Fuck now I feel dumb

 

[CantStopTheMog]

So, it’s quite a cool trick in reality, we don’t really appreciate it, but my initial post mentions my key intuition I remember being told about.

Before I get into it, you need to really understand this wrapper lest it breaks your skull. That key premise is mentioned of, “If I asked you X, would you say Y?” If the god is not random, then the answer to the wrap is Y iff (if and only, sorry we use that a lot in maths…) P is true! Now that’s regardless which is yes or no and whether the god is a fibber or not. The wrap of “if I asked you…” cancels that out.

Now, D is guaranteed to be non-random after my first question even if A is random because if we take the case of A being random, then by the puzzle’s setup, B and C are non-random. A’s answer is just a coin flip but either branch is non-random therefore D is non-random, so that first Q1 is random-safe if you will.

Let’s just do another case review. Imagine A is not random. By the actual lemma, A’s answer to my wrapped Q is going to be “da” if and only (iff but I don’t want to confuse you) “B is random“ is true, or “ja” if and only “B is random” is false. Therefore if A says “da”, B is now determined to be random, the non-randoms have to be A and C. If A says “ja”, however, B is not random now, so B is either a truth-teller or a fibber. That’s the exact justification.

IDK how well I can explain this via text, but perhaps numbers help you better. Since this is logic at the end of the day, this can easily be extrapolated to numbers and maybe you’ll get it then? This should be enough an explanation,

Fuck now I feel dumb

grok has a like 9000iq tbf

 

[imontheloose]

grok has a like 9000iq tbf

It’s quite good at logic chains since it basically uses human information and applies it.

 

[nobodylovesme]

There are three gods: A, B, and C.

• One always tells the truth (True).
• One always lies (False).
• One answers randomly (Random) — on each question he flips a fair coin to decide whether to answer truthfully or lie.

Each god answers only “da” or “ja” (you do not know which word means “yes” and which means “no”).


You may ask exactly three yes/no questions total.


Each question must be asked to a single god (you may choose which god for each question, and you may ask the same god more than once).


Your task: determine which god is True, which is False, and which is Random.





Constraints to note (important):

• You don’t know whether “da” = yes or “ja” = yes.
• Random’s answer is independent each time (a fair coin decides whether he answers truthfully or falsely on that question).
• Questions must be answerable by yes/no (i.e., framed so a truthful/lying god can respond with yes/no).

Tbh it’s not actually that hard but it requires advanced problem solving skills for sure. For refernce I got the answer in under 2-3 mins, so defo no impossible

Can you solve this problem, saar?

Jack plays a game on a matrix with 100 rows and 99 columns (100x99).
There is exactly one trap on each row, but not on rows 1 or 100.
And there can be only max one trap per column.

Then Jack starts from the first row, and he can move left, right, up, and down one step at a time.
If Jack hits a trap, he will remember its position and the trap stays there (traps never move, and they stay active at all times). Jack will then start at row 1 again.

Problem is, what is the minimum amount of tries Jack has to do to guarantee an ascend from row 1 to row 100?
What is the strategy and the amount?

 

[Gaygymmaxx]

@CantStopTheMog
infer my iq

fellow modern thinker

 

[mrdouchebag]

grok has a like 9000iq tbf

Nah, seriously, the little fucker is ripping the answers from articles and pdfs. He is a FRAUD.