Is 0.99999999999999999…. Equal to 1?

[Lebgfinal]

Assume its 0.9 with infinite periods

 

[halloweed]

Clavicular

 

[Deleted member 77954]

Assume its 0.9 with infinite periods

No

 

[BeanletMogger]

Yes

 

[liberiangrimreaper]

yes haha

 

[psychomandible]

No

 

[Lebgfinal]

No

I think it is
x = 0.9…
10x = 9.9…
10x - x = 9.9… - 0.9…
9x = 9
x = 1
0.999… = 1

 

[haymaker283]

Yes it is.

1/3=0.3333333.....
2/3=0.6666666.....
3/3=0.9999999.....

3/3=1

Therefore it's proven

 

[ElTruecel]

You said your iq was tested at 128 with what test supposedly the same iq as @MoggerGaston

 

[NZb6Air]

nigga trynna beat the low iq accusations

 

[NZb6Air]

You said your iq was tested at 128 with what test supposedly the same iq as @MoggerGaston

test taken on roblox

 

[Lebgfinal]

Yes it is.

1/3=0.3333333.....
2/3=0.6666666.....
3/3=0.9999999.....

3/3=1

Therefore it's proven

x = 0.9…
10x = 9.9…
10x - x = 9.9… - 0.9…
9x = 9
x = 1
0.999… = 1
Also proven with this

 

[Lebgfinal]

nigga trynna beat the low iq accusations

I know the answer i just want to see what people will reply retard

 

[Deleted member 77954]

I think it is
x = 0.9…
10x = 9.9…
10x - x = 9.9… - 0.9…
9x = 9
x = 1
0.999… = 1

You would have to remove x on 9.9
It would be this 10x-x= 9.9... -x

 

[Lebgfinal]

You would have to remove x on 9.9
It would be this 10x-x= 9.9... -x

x is 0.9… ?

 

[Deleted member 56968]

You said your iq was tested at 128 with what test supposedly the same iq as @MoggerGaston

test taken on roblox

brutal iq mog

 

[Deleted member 77954]

x is 0.9… ?

Fuck I'm retarded give me a sec

 

[liberiangrimreaper]

You said your iq was tested at 128 with what test supposedly the same iq as @MoggerGaston

Where he got his results

 

[Lebgfinal]

Where he got his results
View attachment 3205389

I got my iq test in real life so yeah kys

 

[toji.]

Yes, in fact all numbers have in between infinite decimals, the distance from 1 to 2 implies that there are millions of numbers in between before reaching 2 or to reach 1, this principle is what is studied in calculus with respect to limits.

But indeed 0.99999 tends to 1 both on the left (-) and on the right (+), so it is indeed 1, (this is the calculation of lateral limits).

 

[Lebgfinal]

Yes, in fact all numbers have in between infinite decimals, the distance from 1 to 2 implies that there are millions of numbers in between before reaching 2 or to reach 1, this principle is what is studied in calculus with respect to limits.

But indeed 0.99999 tends to 1 both on the left (-) and on the right (+), so it is indeed 1, (this is the calculation of lateral limits).

9.9… has infinitely large decimals which mean is would need 0.001.. infinitely small decimal

 

[Deleted member 77954]

I think it is
x = 0.9…
10x = 9.9…
10x - x = 9.9… - 0.9…
9x = 9
x = 1
0.999… = 1

X=0.9~
Not 1 as 10x is the exact same as 9.9~ so x isn't 1 just 0.9~
X=0.9~

 

[ElTruecel]

I got my iq test in real life so yeah kys

I know you don’t believe in Epigenetics but opinions on neuroplasticity

 

[ChadL1te]

x = 0.9…
10x = 9.9…
10x - x = 9.9… - 0.9…
9x = 9
x = 1
0.999… = 1
Also proven with this

that proof assumes 0.999 repeating is a real number

 

[Lebgfinal]

that proof assumes 0.999 repeating is a real number

It assume 0.99999 has infinite decimals yea

 

[Deleted member 77954]

X=0.9.
10x=9.9.
10x-x=9x=9.9.-0.9.= 8.9.
X=0.9.
@Lebgfinal

 

[Deleted member 52405]

Um... Yes?

 

[Lebgfinal]

X=0.9.
10x=9.9.
10x-x=9x=9.9.-0.9.= 8.9.
X=0.9.
@Lebgfinal

0,99999999 has infinite decimals tho

 

[toji.]

that proof assumes 0.999 repeating is a real number

 

[FastBananaCEO]

Yeah it is because of some mathematical reason but I’m not an expert on math

 

[Deleted member 77954]

0,99999999 has infinite decimals tho

I took that into account let's take
0.9.+0.9.=1.9.
X+x= 2x
Which means that one of the 0.9. can't be bigger than the other so if you subtract 0.9. from 1.9. you'd get 0.9. the second 0.9. used 1 decimal to go from 0.9. to 1
This is hard to explain and I understand if you didn't understand this but in theory it can't become 1

 

[Deleted member 92913]

You can write it as fraction its equal to 1

 

[ChadL1te]

It assume 0.99999 has infinite decimals yea

no, it assumes 0.999 repeating is a real number that exists. Also what u showed is not a proof, its just a series of true statements(based on that assumption). But it doesnt prove that 0.999=1

Thats like me saying 1+1=2. 2+2=4, these holds the fundamental theorem of calculus, therefor thats a proof of the FTC. That dosent prove the FTC nor does what you show prove 1=0.9999

 

[toji.]

I took that into account let's take
0.9.+0.9.=1.9.
X+x= 2x
Which means that one of the 0.9. can't be bigger than the other so if you subtract 0.9. from 1.9. you'd get 0.9. the second 0.9. used 1 decimal to go from 0.9. to 1
This is hard to explain and I understand if you didn't understand this but in theory it can't become 1

Use limits and understand his concept. Leibniz can answer your question.

 

[Deleted member 92913]

Either do infine sum adding up shit or series of equations

 

[Deleted member 77954]

Use limits and understand his concept. Leibniz can answer your question.

Was my math right there?

 

[ChadL1te]

View attachment 3205440

most ppl arent talking about this when they're doing this so called 'proof'

 

[lowinhibcel]

go study math if you really wanna know

 

[Aladin]

1 - 0.99…. = 0.00…. = 0

Aka equal.

 

[incel194012940]

If it's measuring something yes because no tool can measure anything to that accuracy and you'd round up based on the amount of significant figures

If it's abstract no

 

[princeof316]

Assume its 0.9 with infinite periods

yes